Flutter嵌套json解析错误,无法将'Model'赋给参数类型'Map〈String,dynamic>'

oyxsuwqo  于 2022-11-17  发布在  Flutter
关注(0)|答案(1)|浏览(113)

当我解析我的嵌套json时,我的模型中的媒体类可能是空的,我不能检查它是否为空,并且我不能Map我的嵌套元素到我的模型中:

class Product {
  Product({
    required this.id,
    required this.name,
    required this.categoryName,
    this.media,
  });
  late final int id;
  late final String name;
  late final String categoryName;
  List<Media>? media;

  Product.fromJson(Map<String, dynamic> json){
    id = json['id'];
    name = json['name'];
    categoryName = json['category_name'];
    media != null ? (json["media"] as List).map((a) => Media.fromJson(a)).toList() : null;
    // media != null ? List.from(json['media']).map((e)=>Media.fromJson(e)).toList() : null;
  }

  Map<String, dynamic> toJson() {
    final data = <String, dynamic>{};
    data['id'] = id;
    data['name'] = name;
    data['category_name'] = categoryName;
    data['media'] = media!.map((e)=>e.toJson()).toList();
    return data;
  }
}

class Media {
  Media({
    required this.id,
    required this.productId,
    required this.type,
    required this.links,
  });
  late final int id;
  late final int productId;
  late final String type;
  late final Links links;

  Media.fromJson(Map<String, dynamic> json){
    id = json['id'];
    productId = json['product_id'];
    type = json['type'];
    links = Links.fromJson(json['links']);
  }

  Map<String, dynamic> toJson() {
    final _data = <String, dynamic>{};
    _data['id'] = id;
    _data['product_id'] = productId;
    _data['type'] = type;
    _data['links'] = links.toJson();
    return _data;
  }
}

当我尝试用forEach循环它时,我得到:
错误:参数类型'Media'不能赋值给参数类型'Map〈String,dynamic〉'。(参数类型_not_assignable at [yiwumart] lib/catalog_screens/catalog_item.dart:72)

final media = productItem.media!.map((e) => Media.fromJson(e)).toList();
k3bvogb1

k3bvogb11#

尝试

Product.fromJson(Map<String, dynamic> json) {
    id = json['id'];
    name = json['name'];
    categoryName = json['category_name'];
    media = (json["media"] as List?)?.map((a) => Media.fromJson(a)).toList();
  }

相关问题