我在这里所做的就是用其他的东西替换所有需要的双引号，然后删除不需要的双引号，然后再转换回来。

import re
import json

def fix_json_string(st):
    st = re.sub(r'","',"!!",st)
    st = re.sub(r'":"',"--",st)
    st = re.sub(r'{"',"{{",st)
    st = re.sub(r'"}',"}}",st)
    st = st.replace('"','')
    st = re.sub(r'}}','"}',st)
    st = re.sub(r'{{','{"',st)
    st = re.sub(r'--','":"',st)
    st = re.sub(r'!!','","',st)
    return st

broken_string = '{"key1":"my"value","key2":"my"value2"}'
fixed_string = fix_json_string(broken_string)
print(fixed_string)
js = json.dumps(eval(fixed_string))
print(js)

Output -
{"key1":"myvalue","key2":"myvalue2"} # str
{"key1": "myvalue", "key2": "myvalue2"} # converted to json

变量string不是有效的JSON字符串。正确的字符串应为：

string = '{"key1":"my\\"value","key2":"my\\"value2"}'

问题是字符串包含无效的json格式。
字符串'{"key1": "my"value", "key2": "my"value2"}'：key1的值以"my"结尾，其他字符value"与格式不符。
您可以使用字符转义，有效的json将如下所示：
{"key1": "my\"value", "key2": "my\"value2"} .
由于您将其定义为value，因此需要对转义字符进行转义：
string = '{"key1": "my\\"value", "key2": "my\\"value2"}'
网上有很多关于 * 字符转义 * 的教育材料。如果有什么不清楚的地方，我建议去看看
编辑：如果你坚持在代码中修复字符串（我不建议这样做，请参见注解），你可以这样做：

import re
import json
string = '{"key1":"my"value","key2":"my"value2"}'

# finds contents of keys and values, assuming that the key the real key/value ending double quotes 
# followed by one of following characters: ,}:]
m = re.finditer(r'"([^:]+?)"(?:[,}:\]])', string)

new_string = string

for i in reversed(list(m)):
    ss, se = i.span(1)  # first group holds the content
    # escape double backslashes in the content and add all back together
    # note that this is not effective. Bigger amounts of replacements would require other approach of concatanation 
    new_string = new_string[:ss] + new_string[ss:se].replace('"', '\\"') + new_string[se:]

json.loads(new_string)

这里假设真实的的结束双引号后面跟一个,:}]。