我正在尝试扁平化API响应。这是响应
data = [{
"id": 1,
"status": "Public",
"Options": [
{
"id": 8,
"pId": 9
},
{
"id": 10,
"pId": 11
}
]
},
{
"id": 2,
"status": "Public",
"Options": [
{
"id": 12,
"pId": 13
},
{
"id": 14,
"pId": 15
}
]
}
]
我正在尝试这样做(应用ast literal eval,df.pop和json normalize)。
def pop(child_df, column_value):
child_df = child_df.dropna(subset=[column_value])
if isinstance(child_df[column_value][0], str):
print("yes")
child_df[column_value] = child_df[column_value].apply(ast.literal_eval)
normalized_json = [json_normalize(x) for x in child_df.pop(column_value)]
expanded_child_df = child_df.join(pd.concat(normalized_json, ignore_index=True, sort=False).add_prefix(column_value + '_'))
expanded_child_df.columns = [str(col).replace('\r','') for col in expanded_child_df.columns]
expanded_child_df.columns = map(str.lower, expanded_child_df.columns)
return expanded_child_df
df = pd.DataFrame.from_dict(data)
df2 = pop(df,'Options')
这是我得到的输出
id status options_id options_pid
0 1 Public 8 9
1 2 Public 10 11
但是代码跳过了Options
列表中的一些值。
id status options_id options_pid
0 1 Public 8 9
1 1 Public 10 11
2 2 Public 12 13
3 2 Public 14 15
我错过了什么?
3条答案
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您可以用途:
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