当然有可能：

def split_by_country(region_list: pd.Series):
    result = []
    start_idx = None
    for i, region in enumerate(region_list):
        if region.endswith("*") and not region.endswith("**"):
            if start_idx is None:
                start_idx = i
            elif isinstance(start_idx, int):
                result.append(region_list[start_idx: i])
                start_idx = i
    result.append(region_list[start_idx:])
    return result
        
countries = split_by_country(regions_s) 
countries

上面的代码将把区域的序列/列表拆分成列表的列表。每个子列表都以国家名称开始（索引0）。然后你可以这样做：

country_dict = {country[0]: split_by_region(country[1:])
                for country in countries}

split_by_region与split_by_country by相同，但条件不同（region.endswith("*") and not region.endswith("**")〉region.endswith("**")）
最后是（下面的代码我写的时候没有检查，所以可能包含一些语法错误）：

result_df = pd.DataFrame(columns=["country","subregion","city"])
for i, (country, subregions) in enumerate(country_dict.iteritems()):
    for subregion, city in subregions.iteritems():
        result_df.loc[i] = [country, subregion, city]