我尝试在我的eclipse maven项目中使用QueryDSL。这些是依赖项。

<properties>
        <!-- The main class to start by executing java -jar -->
        <start-class>my.app.market.DBApp</start-class>
        <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
        <maven.compiler.source>1.8</maven.compiler.source>
        <maven.compiler.target>1.8</maven.compiler.target>
        <querydsl.version>4.1.4</querydsl.version>
        <apt-maven-plugin.version>1.1.3</apt-maven-plugin.version>

</properties>

<dependency>
            <groupId>com.querydsl</groupId>
            <artifactId>querydsl-apt</artifactId>
            <version>4.1.4</version>
            <scope>provided</scope>
        </dependency>
        <dependency>
            <groupId>com.querydsl</groupId>
            <artifactId>querydsl-jpa</artifactId>
            <version>4.1.4</version>
        </dependency>
        <dependency>
            <groupId>org.slf4j</groupId>
            <artifactId>slf4j-log4j12</artifactId>
            <version>1.6.1</version>
        </dependency>

<build>
        <plugins>
            <plugin>
                <groupId>com.mysema.maven</groupId>
                <artifactId>apt-maven-plugin</artifactId>
                <version>1.1.3</version>
                <executions>
                    <execution>
                        <goals>
                            <goal>process</goal>
                        </goals>
                        <configuration>
                            <outputDirectory>target/generated-sources</outputDirectory>
                            <processor>com.querydsl.apt.jpa.JPAAnnotationProcessor</processor>
                        </configuration>
                    </execution>
                </executions>
            </plugin>
        </plugins>
    </build>

在此之后，我尝试编写查询。

@Repository
public class QueryDSLRepo {

    @PersistenceContext
    private EntityManager em;

    public ReportingParamDAO save(final ReportingParamDAO reportingParamDAO) {
        em.persist(reportingParamDAO);
        return reportingParamDAO;
    }

    public List<ReportingParamDAO> findreportingParamDAOsByIdQueryDSL(final Integer id) {
        final JPAQuery<ReportingParamDAO> query = new JPAQuery<>(em);
        final QReportingParamDAO reportingParamDAO = QReportingParamDAO.reportingParamDAO;

        return query.from(reportingParamDAO).where(reportingParamDAO.id.eq(id)).fetch();
    }

}

但我得到了错误

QReportingParamDAO cannot be resolved to a type

注意：ReportingParamDAO是一个实体类。
这意味着我的DAO的Q类型类没有生成。我不知道为什么它没有生成。我需要做其他的事情吗？我遇到了this帖子，但是用户正在处理IntelliJ，我似乎不能使它在我的情况下工作。有人能帮助我吗？谢谢！！