groovy Jenkinsfile字符串连接文件名

13z8s7eq 于 2022-11-21 发布在 Jenkins

关注(0)|答案(1)|浏览(158)

天啊，这能有多难....试图重命名磁盘上的文件。

stage('upload binaries')
{
    steps
    {
        dir ("firmware")
        {
            script {
                version = readFile("app/source/version.txt")
            }
            script {
                newfilename = "app/build-app/app${version}.bin"
            }
        

            echo "hello....!"
            echo "$version"
            echo "$newfilename"

            sh "mv app/build-app/app.bin app/build-app/app$version.bin"
            upload_bin_file($newfilename)
        }
    }
}

输出此

Running in /var/jenkins_home/workspace/y_feature_upload-labelled-binary/firmware
[Pipeline] {
[Pipeline] script
[Pipeline] {
[Pipeline] readFile
[Pipeline] }
[Pipeline] // script
[Pipeline] script
[Pipeline] {
[Pipeline] }
[Pipeline] // script
[Pipeline] echo
hello....!
[Pipeline] echo
v1.0.51

[Pipeline] echo
app/build-app/appv1.0.51
.bin
[Pipeline] }
[Pipeline] // dir
[Pipeline] }
[Pipeline] // stage

无论我尝试什么，它都不会附加“.bin”部分。