kubernetes 使用包含子字符串的kubectl删除pod

rdrgkggo 于 2022-11-21 发布在 Kubernetes

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当我运行命令kubectl get pods | grep "apisix"时，我得到以下数据

apisix-dev-78549978b7-pvh2v                           1/1     Running             6 (4m19s ago)   8m14s
apisix-dev-dashboard-646df79bf-mwkpc                  1/1     Running             6 (4m35s ago)   8m12s
apisix-dev-etcd-0                                     1/1     Running             0               8m12s
apisix-dev-etcd-1                                     1/1     Running             0               8m11s
apisix-dev-etcd-2                                     0/1     CrashLoopBackOff    4 (24s ago)     8m11s
apisix-dev-ingress-controller-58f7887759-28cm9        1/1     Running             0               8m11s
apisix-dev-ingress-controller-6cc65c7cb5-k6dx2        0/1     Init:0/1            0               8m9s

是否有办法删除所有包含单词apisix的pod，而不是在kubectl delete命令中提及每个pod名称？

kubernetes

来源：https://stackoverflow.com/questions/74472882/delete-pods-using-kubectl-containing-a-substring

2条答案

按热度按时间

mnemlml81#

您可以运行一个简单的命令：

kubectl delete pod $(kubectl get pod | grep apisix | awk '{print $1}')

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g0czyy6m2#

选择（然后可能删除）一组Pod的常用方法是通过selector标签。
例如，假设存在值为apisix的正确标签app：

# Find which Pods are selected (just to be sure)
kubectl get pod --selector=app=apisix

# Delete them (probably with --dry-run=client, if still unsure about what is selected)
kubectl delete pod --selector=app=apisix

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kubernetes 使用包含子字符串的kubectl删除pod

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