数据来源：

[
  {
    "name": "Gates of Olympus",
    "slug": {
      "_type": "slug",
      "current": "gates-of-olympus"
    }
  },
  {
    "name": "Floating Dragon",
    "slug": {
      "_type": "slug",
      "current": "floating-dragon"
    }
  },
  {
    "name": "Buffalo King Megaways",
    "slug": {
      "_type": "slug",
      "current": "buffalo-king-megaways"
    }
  },
  {
    "name": "Fruit Party",
    "slug": {
      "_type": "slug",
      "current": "fruit-party"
    }
  }
]

如何仅查询具有slug gates-of-olympus的对象？
编码：

export const getServerSideProps = async ({params}:any) => {
    
    const query = `*[_type=="game"]{
    name,
    slug,
    }`;
  
    const games = await sanityClient.fetch(query);
  
    return {
      props: {
        games,
      },
    };
  };

slug通过上下文（params.game）获得。
我也试过，

*[_type=="game" && slug.current == ${params.game}] but still returns all data.