我有带方括号的日期**[2014-11-08 06：27：00.0]，并希望将其删除。
预计产出为2014-11-08 06：27：00.0**

val conf = new SparkConf(true)
   .set("spark.cassandra.connection.host", "127.0.0.1").setAppName("CasteDate").setMaster("local[*]")
   .set("spark.cassandra.connection.port", "9042")
   .set("spark.driver.allowMultipleContexts", "true")
   .set("spark.streaming.receiver.writeAheadLog.enable", "true")

val sc = new SparkContext(conf)

val ssc = new StreamingContext(sc, Seconds(1))
val csc=new CassandraSQLContext(sc)

val sqlContext = new org.apache.spark.sql.SQLContext(sc)

var input: SimpleDateFormat   = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S")
input.setTimeZone(TimeZone.getTimeZone("GMT"))
var dia: SimpleDateFormat  = new SimpleDateFormat("dd")
var mes: SimpleDateFormat = new SimpleDateFormat("MM")
var ano: SimpleDateFormat = new SimpleDateFormat("yyyy")
var horas: SimpleDateFormat = new SimpleDateFormat("HH")
var minutos: SimpleDateFormat  = new SimpleDateFormat("mm")

val data=csc.sql("SELECT timecol from smartgrids.analyzer_temp").collect()

import sqlContext.implicits._

val result = data.map(row => {
                         val day = dia.format(input.parse(row.toString()))
                         val month = mes.format(input.parse(row.toString()))
                         val year = ano.format(input.parse(row.toString()))
                         val hour = horas.format(input.parse(row.toString()))
                         val minute = minutos.format(input.parse(row.toString()))
                             })

val collection = sc.parallelize(Seq(("day", 2), ("month", 2), ("year", 4), ("hour", 2), ("minute", 2)))
collection.saveToCassandra("features", "datepart", SomeColumns("day", "month", "year", "hour", "minute"))
sc.stop()

执行此代码后，我收到错误：

java.text.ParseException: Unparseable date: "[2015-08-20 21:01:00.0]" 
   at java.text.DateFormat.parse(DateFormat.java:366)

我认为这个错误是因为日期有方括号，所以，我想删除它。