我的输入文件中有一行文本，分为六列。列之间用分号分隔。
以下是输入文件示例：
A1;example;10;0;55;2.44
我只看第三列的数字，这里是10，所以它的位数之和是1，根据任务要求，总和必须是7
我读了这一行，把它存到缓冲区里，然后逐字节移到第三个comumn开始的地方。

; Save line into buffer
    call procGetLine
    
    ; Skip one column
    mov di, inputBuffer
    .whileNotSemicolon:
        cmp di, byte ';'
        je .semicolon
        inc di
        jmp .whileNotSemicolon
        .semicolon:
            inc di

    ; Do some calculations with second column and move to the start of third column
    ; ............

    ; Call function that calculates sum of number digits in third column
    call procDigitsSum
    cmp [digitsSum], word 7
    je .isSeven

procDigitsSum函数：

procDigitsSum
    push si
    push ax
    push dx
    push cx
    push bx

        mov [digitsSum], word 0
        mov si, 0
        .loop:
            mov cl, [di]
            inc di

            cmp cl, byte ';'
            je .columnEnd

            ; ASCIIZ for using it in function later
            mov byte [thirdColumnNumber+si], cl     
            mov byte [thirdColumnNumber+si+1], 0    
            inc si
            jmp .loop

        .columnEnd
            mov dx, thirdColumnNumber
            mov di, dx
            .secondLoop:
                ; Guessing mistake lies somewhere here
                mov dl, [di]
                inc di
                cmp dl, byte 0
                je .endLoop

                add [digitsSum], dl
                add [digitsSum], byte 30h

                jmp .secondLoop

        .endLoop
    pop bx
    pop cx
    pop dx
    pop ax
    pop si
    ret

procGetLine函数以防万一，但它似乎工作得很好：

procGetLine:
    push ax
    push bx
    push cx
    push si

        mov bx, [inputFileDescriptor]
        mov si, 0

        .loop
            call procFGetChar
            cmp ax, 0
            je .endOfFile
            jc .endOfFile

            mov [inputBuffer+si], cl
            inc si

            cmp cl, 0Ah
            je .endOfLine

            jmp .loop

        .endOfFile:
            mov [lastLine], byte 1
        .endOfLine:
            mov [inputBuffer+si], byte '$'
            mov [bytesRead], si

    pop si
    pop cx
    pop bx
    pop ax
    ret