我下面的代码，由于某种原因，只输出数字的最后2位数字，不管数字有多长......有人能告诉我这个问题/如何解决吗？当然我想打印出整个数字，但它不允许我。请帮助，谢谢

global _start

section .text
_start:
    mov eax, 6789       ; The number to be printed
    mov ebx, 0          ; count the digits
    mov ecx, 10         ; divisor

divide:
    mov edx, 0
    div ecx             ; divide the number into eax and edx | for 6789, eax = 678, edx = 9
    push ebx            ; push current count into the stack
    inc ebx             ; increase the number of digits
    push edx            ; push the value of remainder into the stack
    cmp eax, 0          ; check if eax = 0, means all digits are pushed into the stack
    jne divide

; Stack at the end of divide: (entry from left): 6, 3, 7, 2, 8, 1, 9, 0 ]
print:
    pop edx             ; take out the value pushed previously in the stack
    add edx, 0x30       ; Convert to ASCII
    mov [digit], edx    ; Save the value of edx to digit
    mov eax, 4          ;\
    mov ebx, 1          ; |---> use sys_write to print on screen
    mov ecx, digit      ; |
    mov edx, 1          ;/
    int 0x80

    pop ebx             ; Restore value of count to ebx from the stack
    cmp ebx, 0          ; compare whether count is equal to 0
    jnz print           ; if not 0, go back to print and print the next digit on the screen

concl:
    mov eax, 1
    mov ebx, 0
    int 0x80

section .data
    digit db 0

我已经使用gdb-（GEF）进行调试，堆栈似乎工作正常，所有寄存器也是如此。
以下数字的输出示例为：6789输出为：89