我的表格如下:
1-医疗_公司:
- medical_company_id外键在帐户_实体表帐户_实体_id列上(不是PK)
- 栏1
- 栏2
- 第3栏
2-账户_实体:
*帐户实体标识(pk)
- 栏1
- 栏2
- 第3栏
3-人:
*人员标识(pk)
- 栏1
- 栏2
- 第3栏
4-雇员_公司:
*medical_company表上的公司标识外键,该表位于medical_company_id上
*person表上的雇员标识外键person_id
- 栏1
- 栏2
实体:
1-医疗公司:
@SuppressWarnings("serial")
@Entity
@Table(name = "medical_company")
public class MedicalCompany implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id", unique = true, nullable = false)
@Basic(fetch = FetchType.EAGER)
private Long id;
@OneToOne
@Cascade(value = { CascadeType.ALL })
@JoinColumn(name = "medical_company_id", referencedColumnName = "account_entity_id")
private AccountEntity accountEntity;
}
2-帐户实体:
@SuppressWarnings("serial")
@Entity
@Table(name = "account_entity")
public class AccountEntity implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "account_entity_id", unique = true, nullable = false)
@Basic(fetch = FetchType.EAGER)
private Long id;
}
3-联系人:
@SuppressWarnings("serial")
@Entity
@Table(name = "person")
public class Person implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "person_id", unique = true, nullable = false)
@Basic(fetch = FetchType.EAGER)
private Long id;
}
4-员工公司ID:
@SuppressWarnings("serial")
@Embeddable
public class EmployeeCompanyId implements Serializable {
@ManyToOne
private Person person;
@ManyToOne
private MedicalCompany medicalCompany;
@Size(max = 150, message = "{long.value}")
@Column(name = "title_text", length = 150, nullable = true)
private String titleText;
@Column(name = "employee_manager")
private long employeeManager;
}
5-员工公司:
@SuppressWarnings("serial")
@Entity
@Table(name = "employee_company")
@AssociationOverrides(value = {
@AssociationOverride(name = "pk.medicalCompany", joinColumns = @JoinColumn(referencedColumnName = "medical_company_id")),
@AssociationOverride(name = "pk.person", joinColumns = @JoinColumn(referencedColumnName = "person_id")),
@AssociationOverride(name = "pk.titleText"),
@AssociationOverride(name = "pk.employeeManager") })
public class EmployeeCompany implements Serializable {
@EmbeddedId
private EmployeeCompanyId pk = new EmployeeCompanyId();
@Transient
public void setEmployeeManager(long employeeManager) {
this.pk.setEmployeeManager(employeeManager);
}
public long getEmployeeManager() {
return pk.getEmployeeManager();
}
@Transient
public void setTitleText(String titleText) {
this.pk.setTitleText(titleText);
}
public String getTitleText() {
return pk.getTitleText();
}
public void setPerson(Person person) {
this.pk.setPerson(person);
}
@Transient
public Person getPerson() {
return this.pk.getPerson();
}
public void setMedicalCompany(MedicalCompany medicalCompany) {
this.pk.setMedicalCompany(medicalCompany);
}
@Transient
public MedicalCompany getMedicalCompany() {
return this.pk.getMedicalCompany();
}
public void setPk(EmployeeCompanyId pk) {
this.pk = pk;
}
public EmployeeCompanyId getPk() {
return pk;
}
}
尝试运行应用程序时,我收到以下错误:
org.hibernate.MappingException: Unable to find column with logical name: medical_company_id in org.hibernate.mapping.Table(medical_company) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:550)
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:126)
at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:110)
at org.hibernate.cfg.AnnotationConfiguration.processFkSecondPassInOrder(AnnotationConfiguration.java:520)
at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:380)
at org.hibernate.cfg.Configuration.buildMappings(Configuration.java:1206)
at org.springframework.orm.hibernate3.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:717)
at org.springframework.orm.hibernate3.AbstractSessionFactoryBean.afterPropertiesSet(AbstractSessionFactoryBean.java:211)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1477)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1417)
请告诉我为什么我得到这个错误,以及如何解决它。
5条答案
按热度按时间cdmah0mi1#
我将删除MedicalCompany中的referencedColumnName属性,因为您正在命名AccountEntity的主键字段。我认为只有在它引用非主键字段时才有必要。
roejwanj2#
此错误告诉您,medical_company表中没有名为medical_company_id的列。medical_company中的列仅称为id。
6jjcrrmo3#
我在不同的情况下收到了相同的错误。我尝试用字符串键连接2个表。此代码块发送了相同的错误。
我通过添加列和Fetch类型解决了问题(我在实体中有2个连接,因此需要添加FetchMode)=〉
pnwntuvh4#
对于那些遇到这个问题并正在使用
globally_quoted_identifiers
的人来说,这对我很有帮助:变更
结束日期
请注意
referencedColumnName
值周围的反勾号。1bqhqjot5#
确保父实体的主键名称:
@Column(name = "id")
与子实体中referencedColumnName(外键)的名称相同:@JoinColumn(name = "created_by", referencedColumnName = "id")
即:id = id