我将使用正则表达式解析出需要的部分并将其作为对象的属性输出：

$dateToSearch = '2022-08-21' 
$regex = "^(?<date>$dateToSearch)\s+(?<time>\d{2}:\d{2}:\d{2})\s+(?<number>[a-z\d]+)\s+(?<type>\w+)\s+=\.*"

Get-Content -Path '\log.log' | Where-Object { $_ -match $regex } | 
    Select-Object @{Name = 'Date'; Expression = {$matches['date']}},
                  @{Name = 'Time'; Expression = {$matches['time']}},
                  @{Name = 'Number'; Expression = {$matches['number']}},
                  @{Name = 'Type'; Expression = {$matches['type']}} |
    Export-CSV -Path '\output.csv' -NoTypeInformation

或者使用循环而不是计算属性：

$dateToSearch = '2022-08-21' 
$regex = "^(?<date>$dateToSearch)\s+(?<time>\d{2}:\d{2}:\d{2})\s+(?<number>[a-z\d]+)\s+(?<type>\w+)\s+=\.*"

Get-Content -Path '\log.log' | Where-Object { $_ -match $regex } | ForEach-Object {
    [PsCustomObject]@{
        Date   = $matches['date']
        Time   = $matches['time']
        Number = $matches['number']
        Type   = $matches['type']
    }
} | Export-CSV -Path '\output.csv' -NoTypeInformation

测试结果

Date       Time     Number Type 
----       ----     ------ ---- 
2022-08-21 09:06:09 15SS3B Equip

你要找这样的东西，我做了一行，同样可以做多行也行。

$line = "2022-06-21 09:06:09 15SS1B Equip = Z39 Text -0003254 Equipment has been added on-line"
$data = $line.Split("=")[0]
$result = $data.Split(" ") # A Space in between quotes
[pscustomObject]@{
   Date = $result[0]
   Time = $result[1]
   Number = $result[2]
   Type = $result[3]
}