问题在于你对人力资源的评估会导致状态。正如所写的，状态总是红色的。这里有一个解决办法：
第一个

你的问题有答案，但你的代码看起来比它需要的复杂得多。考虑利用Intl.DateTimeFormat构造函数和formatToParts。下面的代码只使用时间，你可能想包括星期几、假日等。

function isMarketOpen(loc, tz, open, close, date = new Date()) {
  // Get time in particular location for given date
  let f = new Intl.DateTimeFormat('default', {
    hour: '2-digit',
    minute: '2-digit',
    timeZone: tz,
    timeZoneName: 'short'
  });
  let {hour, minute, timeZoneName} = f.formatToParts(date).reduce((acc, part) => {
    if (part.type != "literal") {
      acc[part.type] = part.value;
    }
    return acc;
  }, Object.create(null));
  // Return based on whether it's between open and close or not
  let time = hour*60 + minute*1;
  return `${loc} is ${time >= open && time <= close? 'open':'closed'} (${hour}:${minute} ${timeZoneName}).`;
}

// Sample data
let data = [
  {loc: 'New York',
   tz:  'America/New_York',
   open: 540, // Minutes
   close: 1020
  },{
   loc: 'London',
   tz:  'Europe/London',
   open: 480,
   close: 960
  }
];
// Show open/closed
data.forEach(obj => console.log(
  isMarketOpen(obj.loc, obj.tz, obj.open, obj.close)
));