我答应阵有问题：我在交换机内调用一个函数，该函数从API加载一个数组。示例：

let sorted = []
let limit = 10
async function loadPage(slcLimit) {
    let i
    let filter = document.getElementById("show-filter").value

    if (sorted.length == 0) {
        switch (filter) {
            case "1":
                let realWoolPromiseAsc = await Promise.resolve(realWool(pagingPouches))
                    .then((realWoolArr) => {
                        sorted = realWoolArr.sort((a, b) => parseFloat(a.realWool) - parseFloat(b.realWool));
                        return sorted
                    })
                break;
            case "2":
                let realWoolPromiseDesc = await Promise.resolve(realWool(pagingPouches))
                    .then((realWoolArr) => {
                        sorted = realWoolArr.sort((a, b) => parseFloat(b.realWool) - parseFloat(a.realWool));
                        return sorted
                    })
                break;
        }
    }

        for (i = startingLimit; i < (startingLimit + limit); i++) {
            console.log(sorted[i].ID + " - " + sorted[i].price)
        }
}

真毛功能

window.realWool = async function realWool(pouchArr) {
    let divider = 1000000000000000000n;
    let realWoolArray = []
    pouchArr.forEach(async pouch => {
        let availAmount = await pouchContract.amountAvailable(pouch.pouchID)
        availAmount = Number(BigInt(availAmount.toString()) * 100n / divider) / 100
        availAmount = Math.floor(availAmount * 100) / 100
        let rWool = pouch.pouchWool - availAmount
        realWoolArray.push({pouchID: pouch.pouchID, realWool: rWool, pouchTime: pouch.pouchTime})
        //document.getElementById("lockedText" + pouch.pouchID).innerHTML = "Real WOOL: <span class='black'>" + rWool + "</span>"
    });
    return realWoolArray
}

我需要在for循环中使用sorting数组，但我没有定义。我知道我需要使用await或then块，但我不知道如何使用。
谢谢你，谢谢你
我使用了一个timeout，但它不是最佳的，因为有时函数只返回5个对象的数组，有时返回数百个对象（取决于过滤器）

setTimeout(() => {
        for (i = startingLimit; i < (startingLimit + limit); i++) {
            console.log(sorted[i].ID + " - " + sorted[i].price)
        }
}, 5000);