这可以通过make函数来实现，如下所示：

$ cat Makefile
version := v39.0.12.8

version_tuple := $(subst ., ,$(version:v%=%))

version_a := $(word 1,$(version_tuple))
version_b := $(word 2,$(version_tuple))
version_c := $(word 3,$(version_tuple))
version_d := $(word 4,$(version_tuple))

all:
        echo version_tuple = $(version_tuple)
        echo version_a = $(version_a)
        echo version_b = $(version_b)
        echo version_c = $(version_c)
        echo version_d = $(version_d)

输出量：

$ make -s
version_tuple = 39 0 12 8
version_a = 39
version_b = 0
version_c = 12
version_d = 8

使用gmtt，可以对版本号执行glob匹配：

include gmtt/gmtt.mk

version := v39.0.12.8

matchresult := $(call glob-match,$(version),v*.*.*.*)

$(info [$(matchresult)])

major := $(word 2,$(matchresult))
minor := $(word 4,$(matchresult))
bugfix := $(word 6,$(matchresult))
buildcnt := $(word 8,$(matchresult))

$(info Major = $(major))
$(info Minor = $(minor))
$(info Bugfix = $(bugfix))
$(info Buildcnt = $(buildcnt))

$(if $(call int-ge,$(major),39),$(info Major is 39 or higher!))

• 作为其他优秀答案的替代方案，以下是我的首选解决方案。*

生成文件：

split-dot = $(word $2,$(subst ., ,$1))

version := v39.0.12.8
version_a := $(call split-dot,$(version:v%=%),1)
version_b := $(call split-dot,$(version),2)
version_c := $(call split-dot,$(version),3)
version_d := $(call split-dot,$(version),4)

all:
    $(info version_a=$(version_a))
    $(info version_b=$(version_b))
    $(info version_b=$(version_c))
    $(info version_b=$(version_d))

输出：

$ make -s
version_a=39
version_b=0
version_b=12
version_b=8