int main()
{
    int n = 3;
    int a[n] = {1,2,3};

    ...
    in middle of code, value of n can be increased by 10 so I want to have check before cout otherwise       a[10] is out of bound.  
    ...

    cout<<a[n-1];
    return 0;
}

为了解决上述问题，我简单地把一个如果检查。
更正代码：

int main()
{
    int n = 3;
    int a[n] = {1,2,3};
    ...

    In middle of code, value of n can be increased by 10 so I want to have check before cout otherwise       a[10] is out of bound.   
    ...
    if(n<= 3)
    {
         cout<<a[n-1];    
    }
    return 0;
}

是否有其他方法可以避免内存访问越界
我试着用如果检查的基础上的大小。