我一直在努力学习CS50，只是为了学习编程的基础知识。我成功地做了习题集3的复数运算，但我并不真正理解布尔运算是如何工作的。所以具体的问题是：
1)布尔结构是如何工作的？2）何时以及如何调用它？
我正在试着理解使用这个的基本方面。谢谢你的帮助。
代码如下：

#include <cs50.h>
#include <stdio.h>
#include <string.h>

// Max number of candidates
#define MAX 9

// Candidates have name and vote count
typedef struct
{
    string name;
    int votes;
}
candidate;

// Array of candidates
candidate candidates[MAX];

// Number of candidates
int candidate_count;

// Function prototypes
bool vote(string name);
void print_winner(void);

int main(int argc, string argv[])
{
    // Check for invalid usage
    if (argc < 2)
    {
        printf("Usage: plurality [candidate ...]\n");
        return 1;
    }

    // Populate array of candidates
    candidate_count = argc - 1;
    if (candidate_count > MAX)
    {
        printf("Maximum number of candidates is %i\n", MAX);
        return 2;
    }
    for (int i = 0; i < candidate_count; i++)
    {
        candidates[i].name = argv[i + 1];
        candidates[i].votes = 0;
    }

    int voter_count = get_int("Number of voters: ");

    // Loop over all voters
    for (int i = 0; i < voter_count; i++)
    {
        string name = get_string("Vote: ");

        // Check for invalid vote
        if (!vote(name))
        {
            printf("Invalid vote.\n");
        }
    }

    // Display winner of election
    print_winner();
}

// Update vote totals given a new vote
bool vote(string name)
{
   // TODO
   for (int i = 0; i < candidate_count; i++)
   {
       if (strcmp (name, candidates[i].name) == 0)
       {
           candidates[i].votes++;
           return true;
       }
   }
    return false;
}

// Print the winner (or winners) of the election
void print_winner(void)
{
    // TODO
    for (int i = 1; i < candidate_count; i++)
    {
        if (candidates[0].votes < candidates[i].votes)
        candidates[0].votes = candidates[i].votes;
    }
    printf ("%s\n", candidates[0].name);
    for (int i = 1; i < candidate_count; i++)
    {
        if (candidates[0].votes == candidates[i].votes)
        printf ("%s\n", candidates[i].name);
    }
    return;
}