我想创建一个登录方法来发布http request。我使用以下代码将用户数据发布到服务器并获得响应：

import 'dart:convert';
import 'dart:html';
import 'package:flutter/material.dart';
import 'package:http/http.dart' as http;
import '../Services/baseHttp.dart' as base;

class Services {
  late var token = '';

  Future<http.Response> login(String username, String password) async {
    var url = base.BaseURL.loginUrl;
    Map data = {"username": username, "password": password};
    var body = json.encode(data);
    var response = await http.post(Uri.parse(url),
        headers: {
          "Content-Type": "application/json",
          "Accept": "application/json"
        },
        body: body);

    print(response.statusCode);
    token = response.body;
    print(token);
    return response;
  }
}

我试着在方法里面使用try catch：

Future<http.Response> login(String username, String password) async {
try {
    var url = base.BaseURL.loginUrl;
    Map data = {"username": username, "password": password};
    var body = json.encode(data);
    var response = await http.post(Uri.parse(url),
        headers: {
          "Content-Type": "application/json",
          "Accept": "application/json"
        },
        body: body);

    print(response.statusCode);
    token = response.body;
    print(token);
    return response;
    } catch (e) {
      print(e);
    }
}

我想在抛出任何异常时发送statusCode而不是print(e)。我该怎么做呢？