两个最简单的选项是Split-Path -Leaf或对[IO.Path]::GetFileName(...)的API调用。假设您希望从中导出对象以便将来导出，下面是它的外观：

$paths = @"
SharePoint\user\Documents\2021_Changes_v2048.csv
SharePoint\user\Documents\ACB Client Repair\Client MSI's\CE1.3\CE16098\CE16098-Global\Agree.hta
SharePoint\user\Documents\ACB Client Repair\Client MSI's\AgentSetup_881.msi
"@ -split '\r?\n'

$paths | Select-Object @{ N='FileName'; E={ [IO.Path]::GetFileName($_) }}
$paths | Select-Object @{ N='FileName'; E={ Split-Path $_ -Leaf }}

你的文件看起来不像CSV，如果这是整个内容它只是一个文本文件，所以你可以做：

#load file
$content = gc [path]

#split at '\' and output last string
$content | %{($_ -split '\\')[-1]}

#output
2021_Changes_v2048.csv
Agree.hta
AgentSetup_881.msi

您可以使用Split-Path内置函数。
请参阅https://learn.microsoft.com/en-us/powershell/module/microsoft.powershell.management/split-path?view=powershell-7.2#example-2-display-file-names