我尝试在this page上求解Q.22。数据集为here
问题22编写MongoDB查询,查找在众多调查日期中达到“A”级且ISODate“2014-08- 11 T00:00:00 Z”得分为11的餐厅的餐厅ID、名称和等级
数据的格式为:
[
{
"_key": "2451925",
"_id": "restaurants/2451925",
"_rev": "_buC4Kd2---",
"address": {
"building": "1007",
"coord": [
-73.856077,
40.848447
],
"street": "Morris Park Ave",
"zipcode": "10462"
},
"borough": "Bronx",
"cuisine": "Bakery",
"grades": [
{
"date": {
"$date": 1393804800000
},
"grade": "A",
"score": 2
},
{
"date": {
"$date": 1378857600000
},
"grade": "A",
"score": 6
},
{
"date": {
"$date": 1358985600000
},
"grade": "A",
"score": 10
},
{
"date": {
"$date": 1322006400000
},
"grade": "A",
"score": 9
},
{
"date": {
"$date": 1299715200000
},
"grade": "B",
"score": 14
}
],
"name": "Morris Park Bake Shop",
"restaurant_id": "30075445"
},
{
"_key": "2451926",
"_id": "restaurants/2451926",
"_rev": "_buC4Kd2--A",
"address": {
"building": "469",
"coord": [
-73.961704,
40.662942
],
"street": "Flatbush Avenue",
"zipcode": "11225"
},
"borough": "Brooklyn",
"cuisine": "Hamburgers",
"grades": [
{
"date": {
"$date": 1419897600000
},
"grade": "A",
"score": 8
},
{
"date": {
"$date": 1404172800000
},
"grade": "B",
"score": 23
},
{
"date": {
"$date": 1367280000000
},
"grade": "A",
"score": 12
},
{
"date": {
"$date": 1336435200000
},
"grade": "A",
"score": 12
}
],
"name": "Wendy'S",
"restaurant_id": "30112340"
}]
我试图过滤掉上面给定的ISODate的日期。我正在使用date_timestamp函数将上面的日期转换为数据中存储日期的方式。
我无法过滤日期,因为它们似乎被包裹在{"$date”:1393804800000}中。在g中尝试一个循环会说找到的是一个对象,而不是一个集合或数组。应用一个过滤器并用date_timestamp()检查是否相等会返回空值数组[],[]等。
for r in restaurants
for g in r.grades
let d=date_timestamp("2014-08-11T00:00:00Z")
return {date:g.date,target_date:d}
请帮忙,谢谢
1条答案
按热度按时间u5i3ibmn1#
您必须筛选对象内部的字段: