我有以下场景：我设置了一个客户端，它向服务器发送一个异步HTTP请求。客户端接收到一个CompletableFuture。到目前为止，一切工作正常。但是，我无法访问我发送的请求的响应。

completableFuture.get().body()

而是包含请求的状态。更详细地说，

{"cancelled":false,"done":true,"completedExceptionally":false,"numberOfDependents":0}

我怎样才能得到真实的结果？
这是我的代码...
休息控制器

@RestController
public class WorkerJController {

    @Autowired
    private WorkerJService service;

    @GetMapping(value = "/JobList", produces = MediaType.APPLICATION_JSON_VALUE)
    public CompletableFuture<ResponseEntity> getJobListFunction() throws JsonProcessingException, InterruptedException {
        return CompletableFuture.completedFuture(service.getJobListFunction()).thenApply(ResponseEntity::ok);
    }
}

服务

@Service
public class WorkerJService {

    public static ArrayList<someThing> randomList = new ArrayList<>();

    @Async
    public CompletableFuture<String> getJobListFunction() throws JsonProcessingException, InterruptedException {
        randomList.add(new someThing("abc", "dfe"));
        ObjectMapper mapper = new ObjectMapper();
        TimeUnit.SECONDS.sleep(5);
        return CompletableFuture.completedFuture(mapper.writeValueAsString(jobList));
    }
}

异步配置

@Configuration
@EnableAsync
public class AsyncConfig {

    @Bean(name = "taskExecutor")
    public Executor taskExecutor(){
        ThreadPoolTaskExecutor executor = new ThreadPoolTaskExecutor();
        executor.setCorePoolSize(3);
        executor.setMaxPoolSize(3);
        executor.setQueueCapacity(100);
        executor.setThreadNamePrefix("AsynchThread-");
        executor.initialize();
        return executor;

我发送HTTP请求如下：

HttpClient client = HttpClient.newBuilder()
        .version(HttpClient.Version.HTTP_1_1)
        .followRedirects(HttpClient.Redirect.NORMAL)
        .connectTimeout(Duration.ofSeconds(20))
        .build();

HttpRequest request = HttpRequest.newBuilder()
        .uri(URI.create("http://localhost:8080/JobList"))
        .timeout(Duration.ofMinutes(2))
        .GET()
        .build();

CompletableFuture<HttpResponse<String>> cf = client
        .sendAsync(request, HttpResponse.BodyHandlers.ofString());