我使用下面的代码来检测操作符沿着非英语字符的使用。

/**
 * Prepares a unicode aware RegEx pattern for operators
 *
 * \b (word boundary - wb) can be written as (?:(?<=^)(?=\w)|(?<=\w)(?=$)|(?<=\W)(?=\w)|(?<=\w)(?=\W))
 * \B (non-word boundary - nwb) can be written as (?:(?<=^)(?=\W)|(?<=\W)(?=$)|(?<=\W)(?=\W)|(?<=\w)(?=\w))
 * Unicode-aware \w pattern is [\p{Alphabetic}\p{Mark}\p{Decimal_Number}\p{Connector_Punctuation}\p{Join_Control}]
 *
 */

const w = String.raw`[\p{Alphabetic}\p{Mark}\p{Decimal_Number}\p{Connector_Punctuation}\p{Join_Control}]`;
const nw = String.raw`[^\p{Alphabetic}\p{Mark}\p{Decimal_Number}\p{Connector_Punctuation}\p{Join_Control}]`;
const uwb = String.raw`(?:(?<=^)(?=${w})|(?<=${w})(?=$)|(?<=${nw})(?=${w})|(?<=${w})(?=${nw}))`;
const unwb = String.raw`(?:(?<=^)(?=${nw})|(?<=${nw})(?=$)|(?<=${nw})(?=${nw})|(?<=${w})(?=${w}))`;

const OPERATOR_REGEX = new RegExp(
  String.raw`(?!${unwb}"[^"“”]*)${uwb}(and|or|not|exclude)(?=.*\s)${uwb}(?![^"“”]*"${unwb})`,
  'giu'
);

const query1 = '(Java or "化粧" or 化粧品)';
const query2 = '(Java or 化粧 or 化粧品)';

console.log(query1.split(OPERATOR_REGEX));
console.log(query2.split(OPERATOR_REGEX));

这是一个令人印象深刻的方法answered here，但Safari浏览器不支持lookbehind正则表达式模式(Lookbehind in JS regular expressions)。
有什么好的方法可以让这种逻辑在Safari浏览器中发挥作用？