python 如何在一个简单的游戏中规范回合?

6za6bjd0  于 2022-12-10  发布在  Python
关注(0)|答案(1)|浏览(124)

棋盘游戏需要20轮。棋盘本身是圆形的,这意味着玩家在第10位之后回到第1位。我定义了轮数,但在我的代码中,轮数仍然是随机的。我不明白我的代码有什么问题?

from dataclasses import dataclass
@dataclass
class Player:    
    firstname: str    
    lastname: str   
    coins: int    
    slot: int
    def full_info(self) -> str:
        return f"{self.firstname} {self.lastname} {self.coins} {self.slot}"
    @classmethod
    def from_user_input(cls) -> 'Player':        
        return cls(
            firstname=input("Please enter your first name:"),            
            lastname=input("Please enter your second name: "),            
            coins=200,            
            slot= 0)
minplayer, maxplayer, n = 2, 5, -1
while not(minplayer <= n <= maxplayer):  
    n = int(input(f" Choose a number of players between {minplayer} and {maxplayer}: "))    
playersingame = []   #storing it in the list
for i in range(n):   
    playersingame.append(Player.from_user_input())
print([player.full_info() for player in playersingame])
# The board
board = [[ ] for i in range(10)]
for player in playersingame:    
    board[ player.slot ].append(player)
print(board)
import random    
for player in playersingame:    
    input(f"{player.firstname} {player.lastname}, please press enter to roll your die...")    
    die = random.randint(1,6)    
    print(f"You take {die} step{'s'* (die>1)} forward")    
    board[player.slot].remove(player)    
    player.slot += die    
    board[player.slot].append(player)
print(board)

def shift(seq, n=0):
    a = n % len(seq)
    return seq[-a:] + seq[:-a]
round_counter=1
rounds=30
while (round_counter <= rounds):    
    for player in playersingame:        
        input(f"{player.firstname} {player.lastname}, please press enter to roll your die...")        
        die = random.randint(1,6)        
        print(f"You take {die} step{'s'*(die>1)} forward")        
        board[player.slot].remove(player)        
        player.slot += die
        if board[player.slot] == len(board):
            shift(board)
        board[player.slot-1].append(player)
       
    print(board)
    round_counter = round_counter+1
qojgxg4l

qojgxg4l1#

代替:

player.slot += die
if board[player.slot] == len(board):
    shift(board)
board[player.slot-1].append(player)

尝试:

player.slot = (player.slot + die) % len(board)
board[player.slot].append(player)

您的shift函数返回一个结果,但它从未被赋值,而且从原始代码中也不清楚您打算如何更新所有 * 其他 * 玩家的插槽。
如果有(未说明)为什么公共牌需要在玩家下方移动,请注意,玩家的空位可能超过公共牌的长度,您可能需要测试board[player.slot] >= len(board)。(例如,当player.slot是8并且die是4时,在player.slot += die之后--player.slot现在是12,因为加法是一次完成的并且永远不等于len(board)

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