有没有可能您只是将一个数字列表传递给函数？因为这也可以解释属性错误：AttributeError: 'int' object has no attribute 'Score'
使用列表解析可以很容易地将数字列表转换为记录列表。（或者像第一个例子中的字典）
否则，您的记录可能会缺少“分数”属性（您是否也使用了大写字母？）
我还使用枚举和切片对代码进行了一些优化，并切换了记录而不是值。

包含名称和分数的记录：

它们可以从具有分数的名字的字典中创建：

class Record:
    def __init__(self, Name, Score):
        self.Name = Name
        self.Score = Score
    def __repr__(self):
        return "%s:%d" % (self.Name, self.Score)

def make_scores(scores):
    return [Record(Name, Score) for Name, Score in scores.items()]

def insertion_sort(scores):
    for j, score in enumerate(scores[1:]):
        value = score.Score
        while j >= 0 and scores[j].Score > value:
            scores[j + 1] = scores[j]
            j -= 1
        scores[j + 1] = score
    return scores

scores = make_scores({
    "Alpha": 0,
    "Bravo": 1,
    "Charlie": 2,
    "Delta": 3,
    "Echo": 7
})
print(insertion_sort(scores))
scores = make_scores({
    "Alpha": 7,
    "Bravo": 3,
    "Charlie": 2,
    "Delta": 1,
    "Echo": 0
})
print(insertion_sort(scores))

输出量：

[Alpha:0, Bravo:1, Charlie:2, Delta:3, Echo:7]
[Echo:0, Delta:1, Charlie:2, Bravo:3, Alpha:7]

我希望这是有帮助的。

只包含分数的记录

它们可以从数字列表中创建：

class Record:
    def __init__(self, score):
        self.Score = score
    def __repr__(self):
        return "%d" % self.Score

def make_scores(scores):
    return [Record(score) for score in scores]

def insertion_sort(scores):
    for j, score in enumerate(scores[1:]):
        value = score.Score
        while j >= 0 and scores[j].Score > value:
            scores[j + 1] = scores[j]
            j -= 1
        scores[j + 1] = score
    return scores

scores = make_scores([0,1,2,3,7])
print(insertion_sort(scores))
scores = make_scores([7,3,2,1,0])
print(insertion_sort(scores))

输出量：

[0, 1, 2, 3, 7]
[0, 1, 2, 3, 7]