I generated some spaced out dates in the parms CTE then SELECT the CurrentDate from parms , the Sunday of the week prior to CurrentDate and the Saturday of the week prior to CurrentDate . I'm assuming that you want the dtate range to be Sunday - Saturday.
Sunday - Saturday Ranges

;WITH parms (CurrentDate) AS (
    SELECT DATEADD(dd, -14, CURRENT_TIMESTAMP) UNION 
    SELECT DATEADD(dd, -6, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 2, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 8, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 15, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 20, CURRENT_TIMESTAMP)
)

SELECT CurrentDate
     , LastWeekSunday   = DATEADD(dd, -1, DATEADD(ww, DATEDIFF(ww, 0, CurrentDate) - 1, 0))
     , LastWeekSaturday = DATEADD(dd,  5, DATEADD(ww, DATEDIFF(ww, 0, CurrentDate) - 1, 0))
FROM parms

Monday to Sunday Ranges

;WITH parms (CurrentDate) AS (
    SELECT DATEADD(dd, -14, CURRENT_TIMESTAMP) UNION 
    SELECT DATEADD(dd, -6, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 2, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 8, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 15, CURRENT_TIMESTAMP) UNION
    SELECT DATEADD(dd, 20, CURRENT_TIMESTAMP)
)

SELECT CurrentDate
     , LastWeekMonday   = DATEADD(dd,  0, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CurrentDate)) - 1, 0))
     , LastWeekSunday   = DATEADD(dd,  6, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CurrentDate)) - 1, 0))
FROM parms

If you just want the prior week's Monday to the prior week's Sunday from today rather than from a column of dates you can use this

SELECT CURRENT_TIMESTAMP
     , LastWeekSunday   = DATEADD(dd,  0, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - 1, 0))
     , LastWeekSaturday = DATEADD(dd,  6, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - 1, 0))

This solution is tested and works. I am getting the previous week's Monday and Sunday as upper and lower bounds.

SELECT
    -- 17530101 or 1753-01-01 is the minimum date in SQL Server
    DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 7, '17530101') AS [LowerLimit], -- Last Week's Monday
    DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 1, '17530101') AS [UpperLimit] -- Last Week's Sunday.

Which can be used like this in a real world query:

SELECT
    *
FROM
    SomeTable
WHERE
    SomeTable.[Date] >= DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 7, '17530101') AND
    SomeTable.[Date] <= DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 1, '17530101')

Here are some tests:

1. Leap Year

Current Date: 2016-02-29 00:00:00.000
Results:

LowerLimit                 UpperLimit
2016-02-22 00:00:00.000    2016-02-28 00:00:00.000

2. Last Week was in different year

Current Date: 2016-01-06 00:00:00.000

LowerLimit                 UpperLimit
2015-12-28 00:00:00.000    2016-01-03 00:00:00.000

3. Lower limit in previous month and upper limit in current month

Current Date: 2016-05-04 00:00:00.000

LowerLimit                 UpperLimit
2016-04-25 00:00:00.000    2016-05-01 00:00:00.000

4. Current Date is Sunday

Current Date: 2016-05-08 00:00:00.000

LowerLimit                 UpperLimit
2016-04-25 00:00:00.000    2016-05-01 00:00:00.000

Bill's code worked well, but I needed to make a slight edit if I wanted to get last Sunday to Saturday based on today's date.

select CURRENT_TIMESTAMP, 
LastWeekSunday   = DATEADD(dd,  -1, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - (case datename(weekday,CURRENT_TIMESTAMP) when 'Sunday' then 0 else 1 end), 0)), 
LastWeekSaturday = DATEADD(dd,  5, DATEADD(ww, DATEDIFF(ww, 0, DATEADD(dd, -1, CURRENT_TIMESTAMP)) - (case datename(weekday,CURRENT_TIMESTAMP) when 'Sunday' then 0 else 1 end), 0))

Rgds - Matt

对于所有与日期和日期间隔相关的内容，我几乎总是推荐使用日历表。一个表中包含表示日期、周、月、年、星期几、hiliday、weekand等的列，根据需要预先填充，并对每一列进行索引。每年只有365行。

select min(date), max(date)
from calendar
where week = datepart(week, getdate() - 7)
and year = datepart(year, getdate() - 7)

A shortened version concise syntax
last week, in my vision is the prev adjacent week, so if Im doing report during the week days, I want to receive dates of previous adjacent week Monday to Sunday.

• prev Monday is DATE_ADD(CURDATE(), INTERVAL -(5 + dayofweek(CURDATE())) DAY)
• prev Sunday is DATE_ADD(CURDATE(), INTERVAL -(dayofweek(CURDATE()) - 1) DAY)
• then to take the report from the table need just to integrate those two in SELECT statement

select * from XXX where DateCol between DATE_ADD(CURDATE(), INTERVAL -(5 + dayofweek(CURDATE())) DAY) and DATE_ADD(CURDATE(), INTERVAL -(dayofweek(CURDATE()) - 1) DAY) order by DateCol

I'm late to this party, but wanted to add a simpler way that works for me in SQL Server (when the other examples did not).

select * from table

-- this is for the previous week:

where (datefield >= DATEADD(dd, -1, DATEADD(ww, DATEDIFF(ww, 0, GETDATE()) - 1, 0)) and datefield < DATEADD(dd,  6, DATEADD(ww, DATEDIFF(ww, 0, GETDATE()) - 1, 0)))

-- alternatively, this is for a rolling 7 days:

and DATEDIFF(day, datefield, GETDATE()) between 0 and 7