我在系统上执行了一个命令,并希望看到没有stdout属性的命令结果。
const prompt = require('prompt-sync')({ sigint: true });
const { exec } = require('child_process');
const { stdout } = require('process');
const pathToElevate = Number(prompt('1- suid -2 binary root 3- cap: '))
const userPassword = prompt('Please put the user password(optinal): ')
console.log(stdout)
if (pathToElevate === 1) {
var commandOutput = exec('ls', (error, stdout, stderr) => {
if (error) {
console.log(`error ${error.message}`)
return;
} if (stderr) {
console.log(`stderr ${stderr.message}`)
return;
}
return console.log(stdout) // here is my problem, I want to parse stdout to show the results of ls
})
console.log(commandOutput)
`
我试着在谷歌上搜索,但没有找到任何东西,这是结果。
<ref *1> ChildProcess {
_events: [Object: null prototype] {
close: [Function: exithandler],
error: [Function: errorhandler]
},
_eventsCount: 2,
_maxListeners: undefined,
_closesNeeded: 3,
_closesGot: 0,
connected: false,
signalCode: null,
exitCode: null,
killed: false,
spawnfile: '/bin/sh',
_handle: Process {
onexit: [Function (anonymous)],
pid: 8058,
[Symbol(owner_symbol)]: [Circular *1]
},
spawnargs: [ '/bin/sh', '-c', 'ls' ],
pid: 8058,...
a.out
index.js
node_modules
package.json
package-lock.json
我只要最后一点
1条答案
按热度按时间uurity8g1#
您的代码对我来说工作正常。只需注解掉第8行中的console.log(stdout)和第21行中的console.log(commandOutPut),就可以开始了.. screenshot