reactjs 如何根据所选项目筛选数组

2ic8powd  于 2022-12-12  发布在  React
关注(0)|答案(2)|浏览(177)

我在一个json文件中有一个对象数组:

[
  {
    "department": "Sound Department",
    "subDepartments": [
      "Supervising Sound Editor",
      "Dialog Editor",
      "Sound Designer",
      "Foley Artis",
      "Sound Recordist"
    ]
  },
  {
    "department": "Camera Department",
    "subDepartments": [
      "Camera Operator",
      "Second Assistant Camera",
      "Other Assistant Camera",
      "Steadycam Operator",
      "Focus Puller"
    ]
  },
  {
    "department": "Production Department",
    "subDepartments": [
      "Camera Operator",
      "Second Assistant Camera",
      "Other Assistant Camera",
      "Steadycam Operator",
      "Focus Puller"
    ]
  }
]

从这里我创建了一个部门下拉菜单。从这里我想创建另一个子部门下拉菜单的基础上,哪个部门已被选中。
Departments的下拉菜单工作正常,也可以将该部门存储在一个状态中。我只是不知道如何过滤这些内容。

import React, { useState } from "react";
import "./CreateJobPage3.css"

import Button from "../Input/Button";
import Select from "../Input/Select";
import departmentData from "../Data/departmentSheet.json";

const CreateJobPage3 = (props) => {
    const [department, setDepartment] = useState()
    const [subDepartment, setSubDepartment] = useState()

    const departments = departmentData.map((data) => data.department)

    const subDepartments = departmentData.filter(item => {
        return item.department === department;
      });

    const departmentHandler = (props) =>{
        setDepartment(props)
    }

    const subDepartmentHandler = (props) =>{
        setSubDepartment(props)
    }

  return (
    <>
      <div className="CJP3___inner">
          <Select
            placeholder="Choose Department"
            options={departments}
            value={department}
            onChangeOption={departmentHandler}
          />
          <Select
            placeholder="Choose Department"
            options={subDepartments}
            value={subDepartment}
            onChangeOption={subDepartmentHandler}
            isMulti={true}
          />
      </div>
      <Button className="isGrey formButton" text={"Add Function"} />
    </>
  );
};

export default CreateJobPage3;
kdfy810k

kdfy810k1#

所以你已经有了过滤,你缺少的是从对象中获取subDepartments属性,为此你可以使用map,但是因为你的subDepartments本身是一个数组,我会使用flatMap,否则结果会是[['sub1,'sub2']]

const subDepartments = departmentData.filter(item => {
        return item.department === department;
      }).flatMap(item => item.subDepartments);
x4shl7ld

x4shl7ld2#

这里有两个问题。通过使用Array.filter,您的结果将是整个department对象的数组,而您只需要子部门。在这种情况下,使用Array.find,然后只访问subDepartments数组会快一点。

const departmentData = [{
    "department": "Sound Department",
    "subDepartments": [
      "Supervising Sound Editor",
      "Dialog Editor",
      "Sound Designer",
      "Foley Artis",
      "Sound Recordist"
    ]
  },
  {
    "department": "Camera Department",
    "subDepartments": [
      "Camera Operator",
      "Second Assistant Camera",
      "Other Assistant Camera",
      "Steadycam Operator",
      "Focus Puller"
    ]
  },
  {
    "department": "Production Department",
    "subDepartments": [
      "Camera Operator",
      "Second Assistant Camera",
      "Other Assistant Camera",
      "Steadycam Operator",
      "Focus Puller"
    ]
  }
]

let department = "Production Department"

const subDepartments = departmentData.filter(item => {
  return item.department === department;
});

console.log('Current Method:', subDepartments)

const subDepartmentsNew = departmentData.find(item => {
  return item.department === department;
}).subDepartments;

console.log('New Method:', subDepartmentsNew)

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