我有这样的输入和输出：

• 输入：2个寄存器（R5、R6）中的数字、ASCII字符串的起始地址（指针）
• MOV R5,#HIGH(NUMBER)``MOV R6,#LOW(NUMBER)
• 输出：从给定地址开始的转换ASCII字符串（R7）
• MOV R7,#STR_ADDR_IRAM

代码运行良好，但我必须纠正这个问题：

• 输出字节被逐个计算并放入寄存器R7，但每个新的结果字符覆盖前一个。

MOV A, R6                    ;Get hexadecimal data byte from RAM location R6                   
    MOV R2, A                    ;Store in R2                  
    ANL A, #0FH                  ;Get the lower nibble               
    ACALL ASCII                  ;Convert to ASCII                    
    MOV R7, A                    ;Store the lower digit's ASCII code            
    MOV A, R2                    ;Get back the number              
    SWAP A                       ;Swap nibbles in A                  
    ANL A, #0FH                  ;Get the upper BCD digit               
    ACALL ASCII                  ;Convert to ASCII                      
    MOV R7, A                    ;Store the upper digit´s ASCII code          
    MOV A, R5                    ;Get hexadecimal data byte from RAM location R5                   
    MOV R2, A                    ;Store in R2                    
    ANL A, #0FH                  ;Get the lower nibble                 
    ACALL ASCII                  ;Convert to ASCII                
    MOV R7, A                    ;Store the lower digit's ASCII code           
    MOV A, R2                    ;Get back the number                  
    SWAP A                       ;Swap nibbles in A                         
    ANL A, #0FH                  ;Get the upper BCD digit                
    ACALL ASCII                  ;Convert to ASCII                        
    MOV R7, A                    ;Store the upper digit´s ASCII code            
    RET                                       
    ASCII : CLR C                ;ASCII conversion                      
            MOV R4, A            ;Store A to R4                      
            SUBB A, #0AH         ;Substract accumulator                        
            JC next              ;If carry, jump to next                         
            MOV A, R4            ;No carry so bring back R4 to A                   
            ADD A, #07H          ;No carry, so add 7 to A                     
            SJMP SUM             ;Jump to SUM                     
            next:   MOV A, R4    ;Bring back R4 to A                   
            SUM:    ADD A, #30H  ;Add 30 to A                     
    RET                             
    END