你不必说你是否关心你想要以什么顺序删除列表项。如果你不关心，那么下面的代码展示了你如何实现它。注意，原始列表必须是 * 可变的 *，remove()操作才能起作用

val CHUNK_SIZE = 20
val vehicles = (0..177).map { "Car ${it}" }.toMutableList()

val carListIterator = vehicles.iterator()
val removalChunk = mutableListOf<String>()
while(carListIterator.hasNext()) {
    removalChunk.add(carListIterator.next())
    carListIterator.remove() // this removes the element that was just returned
    if(removalChunk.size >= CHUNK_SIZE || !carListIterator.hasNext()) {
        //store chunk elsewhere
        println("Storing: ${removalChunk.joinToString()}")
        removalChunk.clear()
    }
}