python-3.x 计算一个单词在文本文件中重复的次数

rslzwgfq 于 2022-12-15 发布在 Python

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我需要编写一个程序，提示输入文本文件的名称，并打印频率最高和最低的单词，沿着它们的频率（用空格分隔）。
这是我的短信

I am Sam
Sam I am
That Sam-I-am
That Sam-I-am
I do not like
that Sam-I-am
Do you like
green eggs and ham
I do not like them
Sam-I-am
I do not like
green eggs and ham

代码：

file = open(fname,'r')
dict1 = []
for line in file:
  line = line.lower()
  x = line.split(' ')
  if x in dict1:
    dict1[x] += 1 
  else:
    dict1[x] = 1

然后，我想迭代键和值，并找出最大和最小频率，但到目前为止，我的控制台说
TypeError：列表索引必须是整数或切片，而不是列表
我也不知道那是什么意思。
对于此问题，预期结果为：

Max frequency: i 5
Min frequency: you 1

python-3.x

来源：https://stackoverflow.com/questions/74672514/count-the-number-of-times-a-word-is-repeated-in-a-text-file

1条答案

按热度按时间

bvn4nwqk1#

您正在使用列表而不是字典来存储词频。您不能像这样使用列表来存储键值对，您需要使用字典来代替。下面是如何修改代码以使用字典来存储词频：

file = open(fname,'r')
word_frequencies = {} # use a dictionary to store the word frequencies

for line in file:
    line = line.lower()
    words = line.split(' ')
    for word in words:
        if word in word_frequencies:
            word_frequencies[word] += 1
        else:
            word_frequencies[word] = 1

然后迭代键并找到最小和最大频率

# iterate over the keys and values in the word_frequencies dictionary
# and find the word with the max and min frequency
max_word = None
min_word = None
max_frequency = 0
min_frequency = float('inf')

for word, frequency in word_frequencies.items():
    if frequency > max_frequency:
        max_word = word
        max_frequency = frequency
    if frequency < min_frequency:
        min_word = word
        min_frequency = frequency

打印结果

print("Max frequency:", max_word, max_frequency)
print("Min frequency:", min_word, min_frequency)

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python-3.x 计算一个单词在文本文件中重复的次数

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