首先需要选择感兴趣的列的子集，然后从中找到最小值，然后确定它在哪一列（或者使用argmin同时选择这两个列）（注意，pandas API更倾向于过滤掉行而不是列）。
首先设置一些示例数据

import pandas as pd
import numpy as np
data = np.arange(24).reshape(4,6)
data[1,3:5]=1 # Adjust some values in row 2
df = pd.DataFrame(data, columns=['A', 'B', 'C', 'D', 'E', 'F'])

所以把行和列调换一下

dfT = df.T

获取行2 ==1的列

dfFiltered = dfT[dfT[1] == 1]

查找具有最小值的最小行并获取其索引

dfFiltered.index[dfFiltered[0].argmin()]

对于本例，这将生成'D'。

首先，对于这类应用程序，您确实希望DataFrame被转置，只是不方便对列进行筛选。

import pandas as pd

A = pd.DataFrame(...)
B = A.transpose()

# Now you can filter the drivers where "column" 2 is equal to 1:

C = B[B[2] == 1]

# And find where the minimum of "column" 1 is:

idx = C[1].argmin()

# Finally, find out the driver and its information:

driver = C.index[idx]
info = C.iloc[idx]
# info2 = C.loc[driver] # alternative

# To get the format you want:

print(driver, info.values)