这个问题是错误的本身在黑客等级尝试下面的代码，它将通过所有的测试用例。在黑客等级的原始条件是小于3，但它应该小于13，然后只有你可以通过所有的测试用例，因为单词'ac'是重复7次

import math
import os
import random
import re
import sys

def stringmethod(para, special1, special2, list1, strfind):
    word1=para
    for i in special1:
        word1=word1.replace(i,'')
    word2=word1[0:70]
    word2=word2[-1:-71:-1]
    print(word2)
    l=special2.join(list(word2.replace(" ",'')))
    print(l)
    count=0
    for i in list1:
        if (i in para):count+=1
    if count==len(list1):
        print("Every string in ",list1,"were present")
    else:print("Every string in ",list1,"were not present")
    print(word1.split()[0:20])
    list2=list()
    freq=[]
    for i in word1.split(" "):
        if word1.count(i)<13:
            if i in freq:pass
            else:freq.append(i)
    list2=freq[-1:-21:-1]
    print(list2[-1:-21:-1])
    print(word1.rindex(strfind))
    # Write your code here

if __name__ == '__main__':
    para = input()

    spch1 = input()

    spch2 = input()
    
    qw1_count = int(input().strip())

    qw1 = []

    for _ in range(qw1_count):
        qw1_item = input()
        qw1.append(qw1_item)

    strf = input()

    stringmethod(para, spch1, spch2, qw1, strf)

一些调整

def stringmethod(para: str, special1: str, special2: str, list1: list, strfind: str):
    tpara = para

    """
    Remove all the special characters from para specified in special1 and save them in the variable word1.
    Get the first 70 characters from word1, reverse the strings, save it in variable rword2, 
    and print it.
    """
    for symbol in special1:
        tpara = tpara.replace(symbol, '')
    word1 = tpara
    rword2 = word1[0:70]
    rword2 = rword2[::-1]
    print(rword2)

    """
    Remove all the wide spaces from rword2, join the characters using the special 
    character specified in special2, and print the joint string.
    """
    rword3 = special2.join(rword2.replace(" ", ''))
    print(rword3)

    """
    If every string from list1 is present in para, then format the print statement as follows:
    "Every string in {list1} were present"
    else"Every string in {list1} were not present"
    """

    status = True
    for pattern in list1:
        if pattern not in para:
            status = False
            break

    if status == True:
        print("Every string in", list1, "were present")
    else:
        print("Every string in", list1, "were not present")

    """
    Split every word from word1 and print the first 20 strings as a list.
    Calculate the less frequently used words whose count < 13**. and print the last 20 less frequent 
    words as a list.

    *** Note: Count the words in the order that they appear
    """

    spitted_word = word1.split(' ')
    first_20 = spitted_word[:20]
    print(first_20)

    less_freq_word_lists = []

    for word in spitted_word:
        if word1.count(word) < 13:
            if word not in less_freq_word_lists:
                less_freq_word_lists.append(word)

    print(less_freq_word_lists[-20:])

    """
    Print the last index in word1, where the substring strfind is found.
    """
    print(word1.rfind(strfind))

尝试以下代码

number=word1
splitAll = number.split()
print(splitAll[0:20])
mylist=[]
myDict = dict()
for t in splitAll:
    myDict[t]=myDict.get(t,0)+1
for x,y in myDict.items():
    if(y<3):
        mylist.append(x)
print(mylist[-20:])

请参考博客的完整解释：Here

尝试以下代码

import math
import os
import random
import re
import sys

from collections import Counter
def stringmethod(para, special1, special2, list1, strfind):
    # Write your code here
    word1 = ''.join([i  for i in para if i not in special1] )
    # print( special1)
    rword2 = word1[:70]
    rword2 = rword2[::-1]
    print(rword2)
    
    rjoin = special2.join(rword2.replace(" ",""))
    print(rjoin)
    
    if all(  x in para for x in list1  ):
        print(f"Every string in  {list1} were present")
    else:
        print(f"Every string in  {list1} were not present")
    
    a = word1.split()
    print(a[:20])
    
    l = word1.split()
    f = Counter(l)
    temp =[]
    for k,v in f.items():
        if  v < 3:
            temp.append(k)
    print(temp[-20:])
    
    print(word1.rfind(strfind))

import math
import os
import random
import re
import sys
def stringmethod(para, special1, special2, list1, strfind):
for i in range(len(special1)):
    para=para.replace(special1[i],'')

word1=para
rword2=word1[69::-1]
print(rword2)
print(special2.join(rword2.replace(' ','')))
a=True
for i in list1:
    if i in para:
        a=True
    else:
        a=False
        
if a:
    print(f'Every string in {list1} were present')
else:
    print(f'Every string in {list1} were not present')
        
l1=word1.split()
print(l1[0:20])

l2=list()

for i in l1:
    if l1.count(i) < 3 and i not in l2: 
        l2.append(i)
        
print(l2[-20:])
print(word1.rfind(strfind))

对我来说这下面是运行良好
定义字符串方法（帕拉、特殊1、特殊2、列表1、字符串查找）：

word1 = ''.join(i for i in para if not i in special1)
rword2 = word1[:70][::-1] 
print(rword2)

temp =rword2.replace(" ","").strip()
temp =special2.join(temp)
print(temp)

if all(x in para for x in list1): 
    print("Every string in  {} were present" .format(list1) ) 
else: 
    print("Every string in {} were not present " .format(list1)) 
    
s =word1.split()
print(s[:20])

un_lst=[]
fnl_lst=[]
for i in s:
    if i not in un_lst:
        un_lst.append(i)
        
for i in un_lst:
    s.count(i)<3:
        fnl_lst.append(i)
print(fnl_lst[-20:])

print(word1.rindex(strfind))

如果名称==“主”：帕拉=输入（）

spch1 = input()

spch2 = input()

qw1_count = int(input().strip())

qw1 = []

for _ in range(qw1_count):
    qw1_item = input()
    qw1.append(qw1_item)

strf = input()

stringmethod(para, spch1, spch2, qw1, strf)