c++ 将对向量执行foreach的结果存储< string>在容器中以进行序列化

cwxwcias  于 2022-12-15  发布在  其他
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std::string reg = ("AA00 AAA");
// Open the file for reading
std::ifstream file_in("../data/history/"+reg+".his");

// populate vector with line string from file
std::vector<std::string> contents;
int i;
std::string line;
while(!file_in.eof( )) {
    std::getline(file_in, line);
    contents.emplace_back(line);
    i++;
}
// specify phrases for replacement 
std::string toReplace(" NA ");
std::string dateStamp = dateHelpers::getCurrentDate();

//initialize aux container 
std::vector<std::string> newLineVec;

//perform replacment
std::for_each(contents.begin(), contents.end(),[dateStamp](auto line){  // << was capturing newLineVec Here.
    int index;
    std::cout << "Initial String :" << line << std::endl;
    while((index = line.find("NA")) != std::string::npos) {    //for each location where phrase is present
        line.replace(index, dateStamp.length(), dateStamp);      //remove & replace at that position
        std::cout << "Final String :" << line << std::endl;
        // newLineVec.emplace_back(line);                             // store results ???
         }
     }
);

我的目标是搜索和替换文本文件中的word示例。我似乎不能使用for each的结果填充容器,然后流回输入文件。我的方法在这里是明智的还是我偏离了轨道?
任何帮助都将不胜感激。我已经尝试使代码片段的可复制性最小化,所以任何关于如何改进我的提问的输入也会有很大帮助。
编辑 * 输出示例..

Initial String :james smith 88 broad lane 07474493221 2021/05/12 NA
Final String :james smith 88 broad lane 07474493221 2021/05/12 2022/12/14
Initial String :adam brown  42 church street 07392834769 2022/03/03 NA
Final String :adam brown  42 church street 07392834769 2022/03/03 2022/12/14
Initial String :James smith 88 broad lane 07474493221 2022/09/12 NA
Final String :James smith 88 broad lane 07474493221 2022/09/12 2022/12/14

**edit 2-〉我很抱歉,因为我昨晚一定很累,因为今天早上一切都很好。漫长的一天一定让我更好。这里清理了一下。现在工作的守卫,以避免潜在的分段故障。

void storeLineFiles(std::vector<std::string> &linesVec, const std::string path){
    // Open the file for reading
    std::ifstream file_in(path);

    // populate container with lines from file (strings)
    int i;
    std::string line;
    while(!file_in.eof( )) {
        std::getline(file_in, line);
        linesVec.emplace_back(line);
        i++;
    }
}
void replaceStrContainerWords(std::vector<std::string> &input, const std::string toReplace, const std::string &replacement){
    //initialize aux container
    std::vector<std::string> newLineVec;

    //for each line in input vec + capture env vars
    std::for_each(input.begin(), input.end(),[ &toReplace, &replacement, &newLineVec](auto line){
                      int index;
    //replace all instances of toReplace with replacement
                      while((index = line.find(toReplace)) != std::string::npos) {    //for each location where phrase is present
                          line.replace(index, replacement.length(), replacement);   //remove & replace at that position
                          newLineVec.emplace_back(line);                            // store result temporarily in aux container
                      }
                  }
    );
    input = newLineVec; // copy result to input container for ergonomics.
}
int main(int argc, char *argv[]) {

    std::string reg = ("AA00 AAA");
    std::string path = ("../data/history/" + reg + ".his");
    std::vector<std::string> toChange;
    storeLineFiles(toChange, path);
    for (auto each : toChange) { std::cout << each << "\n"; }

    std::string toReplace("NA");
    std::string dateStamp = dateHelpers::getCurrentDate();
    replaceStrContainerWords(toChange, toReplace, dateStamp);
    for (auto each : toChange) { std::cout << each << "\n"; }
}
iqxoj9l9

iqxoj9l91#

不需要将数据存储在容器中,您可以读取每一行,用替换字符串替换模式字符串,并在单个循环中输出它。
下面是伪代码

open input file
while (not end of file)
{
    read 1 line
    if pattern in line, then replace it
    print output
}
kr98yfug

kr98yfug2#

我创造了一个最小的可复制的例子。
我纠正了你忘记将参数“line”作为引用传递给lambda的问题。因此,在上面的例子中:

std::for_each(input.begin(), input.end(),[ &toReplace, &replacement, &newLineVec](auto line){

所以,单词“line”前面的&
更正后的MRE如下所示,并且可以正常工作:

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>

void replaceStrContainerWords(std::vector<std::string> &input, const std::string &toReplace, const std::string &replacement){

    //for each line in input vec + capture env vars
    std::for_each(input.begin(), input.end(),[ &toReplace, &replacement](auto &line){
        int index;
        //replace all instances of toReplace with replacement
            while((index = line.find(toReplace)) != std::string::npos) {    //for each location where phrase is present
                line.replace(index, replacement.length(), replacement);   //remove & replace at that position
           }
       }
    );
}

int main(int argc, char *argv[]) {

    std::vector<std::string> toChange{
        {"james smith 88 broad lane 07474493221 2021/05/12 NA"},
        {"adam brown  42 church street 07392834769 2022/03/03 NA"}};
        
    std::string toReplace("NA");
    std::string dateStamp{"9988776655"};
    
    replaceStrContainerWords(toChange, toReplace, dateStamp);
    
    for (auto each : toChange) { std::cout << each << "\n"; }
}

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