我想要的示例结果:
我已经做了qrcode扫描和select2。它工作正常。问题是我想在select2下拉菜单中搜索数据“SBD2P3000002”。已经尝试了input标记和它的工作,但使用select2下拉菜单,它不工作。
下面是我代码:
<video id="preview" width="100%"></video>
//this input form working
<input type="text" id="text">
//this not working
<div class="row">
<div class="input-group mb-3 col-md-12">
<select class="custom-select select2" id="add_order" name="variants">
<option selected>Tambah Pesanan...</option>
<?php
if(!empty($variants))
{
foreach ($variants as $key) { ?>
<option
value="<?php echo $key['variant_id'] ?>"
data-sn="<?php echo $key['v_sn'] ?>"
data-price="<?php echo $key['v_kaunter'] ?>"
data-size="<?php echo $key['v_size'] ?>"
data-length="<?php echo $key['v_length'] ?>"
data-width="<?php echo $key['v_width'] ?>"
data-weight="<?php echo $key['v_weight'] ?>"
data-sb="<?php echo $key['v_sb'] ?>"
data-pay="<?php echo $key['v_pay'] ?>"
data-margin="<?php echo $key['v_margin'] ?>"
data-margin_pay="<?php echo $key['v_margin_pay'] ?>"
data-mutu="<?php echo $key['mutu'] ?>"
data-setup_price="<?php echo $key['setup_price'] ?>"
data-serial_berat_price="<?php echo $key['serial_berat'] ?>"
data-product_name="<?php echo $key['product_name'] ?>"
data-product_id="<?php echo $key['product_id'] ?>"
><?= $key['v_sn'] ?></option>
<?php }
}
?>
</select>
</div>
<script type="text/javascript">
let scanner = new Instascan.Scanner({ video: document.getElementById('preview') });
scanner.addListener('scan', function (content) {
console.log(content);
});
Instascan.Camera.getCameras().then(function (cameras) {
if (cameras.length > 0) {
scanner.start(cameras[1]);
} else {
console.error('No cameras found.');
}
}).catch(function (e) {
console.error(e);
});
scanner.addListener('scan',function(c){
$search = document.getElementById("text").value=c;
$("#add_order").data("select2").dropdown.$search.val()
});
</script>
1条答案
按热度按时间nwo49xxi1#
你初始化了select2吗?我在你的代码中没有看到...
要确保DOM已加载,请将脚本封装在此函数中
要在搜索框中输入一个值(已存在),您必须写入: