我正在尝试基于json对象动态复制gulp文件中的文件。我尝试使用merge-stream
包但没有成功。
const DEV_PATH = "./dev/";
const DIST_PATH = "./dist/";
const DEV_PATH_TOOLS = DEV_PATH + "tools/";
const DEV_PATH_COMMON = DEV_PATH + "common/";
const DIST_PATH_TOOLS = DIST_PATH + "tools/";
const TOOLS_DIST_PATH = [
{
"dir" : 'dir1',
"options" : {
"class" : [ "modules/csv/**/*" ]
}
},
{
"dir" : 'dir2',
"options" : {
"class" : [ "modules/csv/CsvImporter.php" ]
}
}
];
const gulp = require('gulp');
const plumber = require('gulp-plumber');
const merged = require('merge-stream')();
gulp.task( 'copy-class', function(){
TOOLS_DIST_PATH.map( t => function () {
var stream = new stream(
gulp.src( t.options.class.map( c => DEV_PATH_COMMON + c ))
.pipe(plumber({
handleError: function (err) {
console.log(err);
this.emit('end');
}
}))
.pipe( gulp.dest( DIST_PATH_TOOLS + t.dir + '/class' ) )
.pipe(plumber({
handleError: function (err) {
console.log(err);
this.emit('end');
}
}))
);
merged.add(stream);
});
return merged.isEmpty() ? null : merged;
});
gulp.task( 'default', gulp.series( 'copy-class' ) );
我得到这个错误:
下列任务未完成:缺省,复制类
你忘了通知异步完成了吗?
我很困惑,有人能帮我吗?
1条答案
按热度按时间ldioqlga1#
我找到一个answer