您可以这样做：

list.sort(key=lambda item:item['date'], reverse=True)

from operator import itemgetter

your_list.sort(key=itemgetter('date'), reverse=True)

相关注解

• 不要用list，dict作为变量名，它们是Python内置的变量名，这会让你的代码难以阅读。
• 您可能需要根据上下文将dictionary替换为tuple或collections.namedtuple或自定义的类似结构的类

from collections import namedtuple
from operator    import itemgetter

Row = namedtuple('Row', 'title date')
rows = [Row(row.title, row.created_on) for row in data]
rows.sort(key=itemgetter(1), reverse=True)

示例：

>>> lst = [Row('a', 1), Row('b', 2)]
>>> lst.sort(key=itemgetter(1), reverse=True)
>>> lst
[Row(title='b', date=2), Row(title='a', date=1)]

或者

>>> from operator import attrgetter
>>> lst = [Row('a', 1), Row('b', 2)]
>>> lst.sort(key=attrgetter('date'), reverse=True)
>>> lst
[Row(title='b', date=2), Row(title='a', date=1)]

以下是namedtuple的内部外观：

>>> Row = namedtuple('Row', 'title date', verbose=True)

class Row(tuple):
        'Row(title, date)'

        __slots__ = ()

        _fields = ('title', 'date')

        def __new__(cls, title, date):
            return tuple.__new__(cls, (title, date))

        @classmethod
        def _make(cls, iterable, new=tuple.__new__, len=len):
            'Make a new Row object from a sequence or iterable'
            result = new(cls, iterable)
            if len(result) != 2:
                raise TypeError('Expected 2 arguments, got %d' % len(result))
            return result

        def __repr__(self):
            return 'Row(title=%r, date=%r)' % self

        def _asdict(t):
            'Return a new dict which maps field names to their values'
            return {'title': t[0], 'date': t[1]}

        def _replace(self, **kwds):
            'Return a new Row object replacing specified fields with new values'

            result = self._make(map(kwds.pop, ('title', 'date'), self))
            if kwds:
                raise ValueError('Got unexpected field names: %r' % kwds.keys())

            return result

        def __getnewargs__(self):
            return tuple(self)

        title = property(itemgetter(0))
        date = property(itemgetter(1))

你可以这样做：

from operator import itemgetter
list.sort(key=itemgetter('date'), reverse=True)

另请参阅：How do I sort a list of dictionaries by a value of the dictionary?

直接对数据（或数据副本）进行排序，然后构建字典列表。使用带有适当键函数（可能是operator.attrgetter）的函数进行排序

如果你喜欢简洁：

data = "data from database"
sorted_data = sorted(
    [{'title': x.title, 'date': x.created_on} for x in data], 
    key=operator.itemgetter('date'),
    reverse=True)