# import engines for code hs (Existing)
import pip
import os
import sys,time,random
import tkinter
from tkinter import *
root = Tk()
# establishes cavas as a object (Existing)
screen = Canvas(root,width = 500, height = 600, background = "light blue")
screen.pack()
# Define some global variable (New)
number = 0
""" funtaion that runs when a button is pressed returning a number
value base on what they choose and then disables the buttons"""
def helloCallBack(num,b1,b2,b3,b4):
我如何使程序识别变量全局?因为他们目前它是不工作.全局编号编号= num
"""if b1 or b2 or b3 or b4 != 0:
b1['state']='disabled'
b2['state']='disabled'
b3['state']='disabled'
b4['state']='disabled'"""
for b in (b1,b2,b3,b4):
if b: b['state'] = 'disabled'
根据指定给num值的值opt 1 -4值指定给按钮的值创建最多四个按钮
def button_maker(num_buttons,opt1,opt2,opt3,opt4):
while True:
master=tkinter.Tk()
master.title("grid() method")
master.geometry("600x150")
如果num_opt等于1,则创建一个按钮
if num_buttons == 1:
button1=tkinter.Button(master, text= opt1,command=lambda : helloCallBack(1,button1,0,0,0))
button1.grid(row=1,column=1)
如果num_opt等于2,则创建两个按钮
elif num_buttons==2:
button1=tkinter.Button(master, text= opt1,command=lambda : helloCallBack(1,button1,0,0,0))
button1.grid(row=1,column=0)
button2=tkinter.Button(master, text= opt2,command=lambda : helloCallBack(2,button1,button2,0,0))
button2.grid(row=6,column=0)
# if num_opt is equal to 3 create three buttons
elif num_buttons==3:
button1=tkinter.Button(master, text=opt1,command=lambda : helloCallBack(1,button1))
button1.grid(row=1,column=0)
button2=tkinter.Button(master, text=opt2, command=lambda : helloCallBack(2,button1,button2,button3,button4))
button2.grid(row=6,column=0)
button3=tkinter.Button(master, text=opt3,command=lambda : helloCallBack(3,button1,button2,button3,button4))
button3.grid(row=8,column=0)
# if num_opt is 4 or over four buttons will be made
else:
button1=tkinter.Button(master, text=opt1,command=lambda : helloCallBack(1,button1,button2,button3,button4))
button1.grid(row=1,column=0)
button2=tkinter.Button(master, text=opt2,command=lambda :helloCallBack(2,button1,button2,button3,button4))
button2.grid(row=6,column=0)
button3=tkinter.Button(master, text=opt3,command=lambda : helloCallBack(3,button1,button2,button3,button4))
button3.grid(row=8,column=0)
button4=tkinter.Button(master, text=opt4,command=lambda : helloCallBack(4,button1,button2,button3,button4))
button4.grid(row=10,column=0)
root.mainloop()
导致文本被键入慢键入速度= 50 #wpm def慢类型(t):对于t中的l:系统标准输出写入(l)系统标准输出刷新()时间休眠(随机.随机()*10.0/打字速度)打印(“”)
保存一个对话树,并通过缓慢键入一个接一个地打印文本。""”
def print_text(my_list):
b=0
space=input("press enter key to continue." )
#key = event.keysym
#print(event.keysym)
for i in my_list:
if space == "":
slow_type(my_list[b])
space=input("")
b=b+1
print_text(["Excellent chioce Mr...","MMM...Mr..."])
#test number value
#print(number)
#test failed
"""creats four buttons on screan when clicked they deactivate and return a number value."""
button_maker(4,str("Tell them your real name!"),"Give them a fake identity ","\"None of your business! \"","\"...\"")
print(number)
# is meant to give different adventures based on what the user chooses
不幸的是,它不工作,因为代码冻结后,按钮是使.如果数字==1:print(input(“编个名和姓:“))
# please !!!SAVE ME!!!
1条答案
按热度按时间nr9pn0ug1#
在Python中,全局变量必须先声明,然后才能在函数中使用,因此应该在开头添加一段代码来声明:
但是,在函数
button_maker()
中似乎存在排印错误,您有4个变量p, k, n, l
未定义,这将返回错误。