我尝试输入字符串，将它们发送到线程，然后将它们转换为整数并相加。我的结果应该是1+1 = 2。但我得到了49+49 = 98

main.c: In function ‘prints’:
main.c:10:7: warning: assignment to ‘int’ from ‘int *’ makes integer from pointer without a cast [-Wint-conversion]
   10 |     c = (int *) string;
      |       ^
main.c:11:9: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
   11 |     a = (int *) string[0];
      |         ^
main.c:11:7: warning: assignment to ‘int’ from ‘int *’ makes integer from pointer without a cast [-Wint-conversion]
   11 |     a = (int *) string[0];
      |       ^
main.c:12:9: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
   12 |     b = (int *) string[1];
      |         ^
main.c:12:7: warning: assignment to ‘int’ from ‘int *’ makes integer from pointer without a cast [-Wint-conversion]
   12 |     b = (int *) string[1];
      |       ^
In function main(): Creating a new thread
11
Given input -1341915086 and sum of 49 and 49 is 98

这是我的代码。最初我把字符串作为静态的，把它们发送到我的线程。打印工作正常，它得到了字符串中所需的值。

#include<stdio.h>
#include <pthread.h>
#include<string.h>
#include <stdlib.h>

void *prints(void *str) {
    int a,b,c, sum;
    char *string = (char *) str;
    printf("%s\n",string);
    c = (int *) string;
    a = (int *) string[0];
    b = (int *) string[1];
    sum =  a+b;
    printf("Given input %d and sum of %d and %d is %d",c,a,b,sum);
}

int main(int argc, char *argv[]) {
    pthread_t threadID;
    const char *word = "11"; // string literals are immutable
    printf("In function main(): Creating a new thread\n");
    int status = pthread_create(&threadID, NULL, prints, (char *)word);
    pthread_join(threadID, NULL);
}