我有3个二维数组，如下所示，这是一系列的数据，以绘制线的图形与关键是时间戳。

const arr1 = [[1641013200000,1881],[1643691600000,38993],[1646110800000,41337],[1648785600000,78856],[1651377600000,117738],[1654056000000,119869],[1656648000000,157799],[1659326400000,196752],[1662004800000,199061],[1664596800000,237034],[1667275200000,239153],[1669870800000,269967]]

const arr2 = [[1641013200000,1302],[1643691600000,3347],[1646110800000,4754],[1648785600000,6948],[1651377600000,9725],[1654056000000,11314],[1656648000000,13787],[1659326400000,16666],[1662004800000,18370],[1664596800000,20876],[1667275200000,22384],[1669870800000,23560]]

const arr3 = [[1643691600000,67350],[1648785600000,134700],[1651377600000,202148],[1654056000000,202270],[1656648000000,269843],[1659326400000,337346],[1662004800000,337470],[1664596800000,404861],[1667275200000,404889],[1669870800000,472239]]

我想绘制另一条系列线，给出所有三个数组值的累计总和（注意：如果两个数组中均不存在时间戳，则添加上一个索引值）

const totalArray = [
[1641013200000,3183],[1643691600000, 109690],[1646110800000, 113441],[1648785600000, 220504],
[1651377600000, 329611],[1654056000000, 333453],[1656648000000, 441429],[1659326400000, 550764],
[1662004800000, 554901],[1664596800000, 662771],[1667275200000, 666426],[1669870800000, 765766]
]

我尝试过这种方法，但由于时间戳不在其中任何一个中，因此某些值不正确
方法：

const arr1 = [[1641013200000,1881],[1643691600000,38993],[1646110800000,41337],[1648785600000,78856],[1651377600000,117738],[1654056000000,119869],[1656648000000,157799],[1659326400000,196752],[1662004800000,199061],[1664596800000,237034],[1667275200000,239153],[1669870800000,269967]];
const arr2 = [[1641013200000,1302],[1643691600000,3347],[1646110800000,4754],[1648785600000,6948],[1651377600000,9725],[1654056000000,11314],[1656648000000,13787],[1659326400000,16666],[1662004800000,18370],[1664596800000,20876],[1667275200000,22384],[1669870800000,23560]];
const arr3 = [[1643691600000,67350],[1648785600000,134700],[1651377600000,202148],[1654056000000,202270],[1656648000000,269843],[1659326400000,337346],[1662004800000,337470],[1664596800000,404861],[1667275200000,404889],[1669870800000,472239]];

const calculateTotal = () => {
    var ret;

    for(let a3 of arr3) {
      var index = arr1.map(function(el){return el[0];}).indexOf(a3[0]);
      console.log(index);
      if (index === -1) {
        ret = arr1[index][0];
        console.log(ret);
      }
    }
    let unsortedArr = arr1.concat(arr2, arr3);
    var sortedArray = unsortedArr.sort((a, b) => a[0] - b[0]);
    var added = addArray(sortedArray);
    console.log("Curent Output: " + JSON.stringify(added));
} 

const addArray = (tuples) => {
    var hash = {},
      keys = [];
      tuples.forEach(function (tuple) {
        var key = tuple[0],
            value = tuple[1];
        if (hash[key] === undefined) {
          keys.push(key);
          hash[key] = value;
        } else {
          hash[key] += value;
        }
      });
      return keys.map(function (key) {
        return([key, hash[key]]);
      });
}

calculateTotal();

[Code沙盒链接][1] [1]：https://codesandbox.io/s/tender-blackburn-rgwns3?file=/src/App.js:1349-1761
有没有可能做到这一点？