powershell 如何查找字符串中的特定位数

vwkv1x7d 于 2022-12-18 发布在 Shell

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我不明白的正则表达式：（我想找出如果路径只包含7位数例如：

C:\Users\3D Objects\1403036 --> the result should be 1403036

C:\Users\358712\1403036 --> the result should be 1403036

等等
我试过：

$FilesPath -match '([\d{1,7}]{7})')

以及

$FilesPath -match '(\d{7})')

型
目前，我正在处理：

$FilesPath = Read-Host -Prompt
if ($Matches[1].Length -eq '7') {
        $FolderNumber = $Matches[1] 
    }

这是不正确的，因为如果路径中包含数字3，则不存在匹配
如果是这种情况：

C:\Users\3D Objects\1403036854 --> More than 7 digits the result should be empty

或

C:\Users\3874113353D Objects\1403036 --> Should return result for 1403036

我没有数组，只想获取是否有正好7位数的数字，如果包含少于或多于7位数，则不需要

powershell

来源：https://stackoverflow.com/questions/74642962/how-to-find-a-specific-number-of-digits-in-string

1条答案

按热度按时间

cetgtptt1#

你是说像这样的东西？

# as example the paths as aray to loop over
'C:\Users\3D Objects\1403036', 'C:\Users\358712\1403036', 
'C:\Users\somewhere\1234567', 'C:\Users\3D Objects\1403036854' | ForEach-Object {
    # return the number anchored at the end of the string with exactly 7 digits
    ([regex]'\D(\d{7})$').Match($_).Groups[1].Value
}

输出：

1403036
1403036
1234567

这一点：

$path = 'C:\Users\3D Objects\1403036'
$result = ([regex]'\D(\d{7})(?:\D|$)').Match($path).Groups[1].Value

型
直接将匹配项赋给变量$result，如果匹配或$null，则将是匹配的数值。Regex方法.Match()不填充$matches数组。
使用regex运算符（它填充$matches数组），您还可以执行以下操作：

if ($path -match '\D(\d{7})(?:\D|$)') {
    $result = $matches[1]
}

正则表达式详细信息：

\D           # Match a single character that is NOT a “digit” (any decimal number in any Unicode script)
(            # Match the regex below and capture its match into backreference number 1
   \d        # Match a single character that is a “digit” (any decimal number in any Unicode script)
      {7}    # Exactly 7 times
)
(?:          # Match the regular expression below
             # Match this alternative (attempting the next alternative only if this one fails)
      \D     # Match a single character that is NOT a “digit” (any decimal number in any Unicode script)
   |
             # Or match this alternative (the entire group fails if this one fails to match)
      $      # Assert position at the end of the string, or before the line break at the end of the string, if any (line feed)
)

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powershell 如何查找字符串中的特定位数

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