user状态切片的数据形状为{ name: string }。

import { combineReducers, configureStore, createSlice } from '@reduxjs/toolkit';

export const userSlice = createSlice({
  name: 'user',
  initialState: {
    name: '',
  },
  reducers: {
    login: (state, action) => {
      state.name = action.payload;
    },
    logout: (state) => {
      state.name = '';
    },
  },
});

export const { login, logout } = userSlice.actions;

export const selectUser = (state: { user: { name: string } }) => state.user;

const store = configureStore({ reducer: combineReducers({ user: userSlice.reducer }) });
console.log(store.getState());
store.subscribe(() => {
  console.log('selectUser:', selectUser(store.getState()));
});

console.log(store.dispatch(login('John')));

日志：

{ user: { name: '' } }
selectUser: { name: 'John' }
{ type: 'user/login', payload: 'John' }

如果你反复检查你的代码，它的罚款。
将redux-toolkit的版本更改为以前的版本，在我的例子中，我使用了1.8.0，一切又开始工作了。
或者删除节点模块并运行npm install或yarn

Redux将根据传递给createSlice函数的initialState值推断state的类型（在您的reducer中），如下所示：

...
initialState: {
  name: '',
}, // type of your state is: { name: string } - notice how it does not have a `user` property!
...

在你的reducer中，你会得到一个状态的WritableDraft示例作为第一个参数，如下所示：

logout: (state: WritableDraft<{ name: string }>) => {
  state.user = null; // 'user' property does not exist in your state type! (as defined in the `initialState`)
},

要完成我认为您正在尝试完成的任务，您所要做的就是将name变量抽象到user属性中，如下所示：

...
initialState: {
  user: { name: '' }
},
reducers: {
  login: (state, action) => {
    state.user = action.payload;
  },
  logout: (state) => {
    state.user = null;
  },
}
...

在这一点上，我建议显式地输入状态和操作负载。
例如：

export type User {
  name: string
}

export type UserState = {
  user: User | null
}

......在你的还原剂中：

login: (state, action: PayloadAction<User>) => {
  state.user = action.payload; // action.payload will be of type 'User'
},
logout: (state) => {
  state.user = null
}

无论如何，您似乎错过了教程中的一些内容，因为在您自己的代码中，您有一个选择器将状态定义为state: { user: { user: any } }。像上面这样显式定义状态类型，应该有助于在将来缓解这些问题。