我需要使用python从字符串中提取字典

f45qwnt8 于 2022-12-21 发布在 Python

关注(0)|答案(2)|浏览(154)

''[ERROR] 2020-10-01T04:46:37.sdfsdqs889dgsdg9dgdf {
"correlation_id": "asdfsdf-dsfasdfa-adfadsf-asdf",
"invocation_timestamp": null,
"invoked_component": "lambda",
"invoker_agent": null,
"message": {
"errorMessage": "Unauthorized",
"statusCode": 401
},
"message_type": "ERROR",
"original_source_app": "",
"response_timestamp": "2020-10-01 04:46:37.121436",
"status": 401,
"target_idp_application": "",
"timezone": "UTC"
}'''

我只需要dict {“相关ID”：“asdfsdf-dsfasdfa-adfadsf-asdf”，“调用时间戳”：空，“调用的组件”：“lambda”，“调用者代理”：空，“消息”：{“错误消息”：“未授权”，“状态代码”：401 }，“消息类型”：“错误”，“原始源应用程序”：“"，“响应时间戳”：“2020-10-01 04：46：37.121436”，“状态”：401，“目标_idp_应用程序”：“"、“时区”：“世界协调时”

python

来源：https://stackoverflow.com/questions/74871568/i-need-to-extract-the-dictionary-from-the-string-using-python

2条答案

按热度按时间

34gzjxbg1#

你可以这样做得到字符串形式

test = '''[ERROR] 2020-10-01T04:46:37.sdfsdqs889dgsdg9dgdf {
"correlation_id": "asdfsdf-dsfasdfa-adfadsf-asdf",
"invocation_timestamp": null,
"invoked_component": "lambda",
"invoker_agent": null,
"message": {
"errorMessage": "Unauthorized",
"statusCode": 401
},
"message_type": "ERROR",
"original_source_app": "",
"response_timestamp": "2020-10-01 04:46:37.121436",
"status": 401,
"target_idp_application": "",
"timezone": "UTC"
}'''

print(test[test.find('{'):]) # find the first '{' and discard all characters before that index in the string

如果你想把它作为一个dict对象

import json
dict_form = json.loads(test[test.find('{'):]) # same as before now sending it to json.loads which converts a string to a dict object (as most requests are sent as a string)
print(dict_form)

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yrwegjxp2#

试试看
res = json.loads（字符串变量）打印（res）
现在您可以使用resdict来访问它。

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