PostgreSQL中的保存点有多糟糕?

amrnrhlw  于 2022-12-23  发布在  PostgreSQL
关注(0)|答案(1)|浏览(129)

我们正在将现有Java应用程序从Oracle DB迁移到PostgreSQL,最近我们注意到PostgreSQL出现以下“意外”行为:
会话#1:

db=> begin;
BEGIN
db=*> select r_object_id from dm_sysobject_s where r_object_id='08000000800027d6' for update;
   r_object_id    
------------------
 08000000800027d6

会话#2:

db=> begin;
BEGIN
db=*> select r_object_id from dm_sysobject_s where r_object_id='08000000800027d6' for update nowait;
ERROR:  could not obtain lock on row in relation "dm_sysobject_s"
db=!> select r_object_id from dm_sysobject_s where r_object_id='08000000800027d6' for update nowait;
ERROR:  current transaction is aborted, commands ignored until end of transaction block

而在Oracle中,一切都按预期运行:
会话#1:

SQL> set autocommit off;
SQL> select r_object_id from dm_sysobject_s where r_object_id='0800012d80000122' for update;

R_OBJECT_ID
----------------
0800012d80000122

会话#2:

SQL> set autocommit off;
SQL> select r_object_id from dm_sysobject_s where r_object_id='0800012d80000122' for update nowait;
select r_object_id from dm_sysobject_s where r_object_id='0800012d80000122' for update nowait
                        *
ERROR at line 1:
ORA-00054: resource busy and acquire with NOWAIT specified or timeout expired

SQL> select r_object_id from dm_sysobject_s where r_object_id='0800012d80000122' for update nowait;
select r_object_id from dm_sysobject_s where r_object_id='0800012d80000122' for update nowait
                        *
ERROR at line 1:
ORA-00054: resource busy and acquire with NOWAIT specified or timeout expired

SQL> commit;

我已经阅读了PSQLException: current transaction is aborted, commands ignored until end of transaction block主题,并了解到保留以前Oracle行为的唯一方法(即在尝试锁定行失败后保持事务活动)是使用保存点。好的,到目前为止一切顺利,下面的代码至少在Supplier<T> supplier仅执行DB操作的情况下执行预期的操作(我确实理解在执行由保存点备份的更复杂操作时,数据库和持久性上下文之间存在差异的风险):

@Override
public <T> T withSavepoint(SessionImplementor session, Supplier<T> supplier) {
    return session.doReturningWork(connection -> {
        DatabaseMetaData metaData = connection.getMetaData();
        if (!metaData.supportsSavepoints()) {
            return supplier.get();
        }
        boolean success = false;
        Savepoint savepoint = null;
        try {
            savepoint = connection.setSavepoint();
            T result = supplier.get();
            success = true;
            return result;
        } finally {
            if (savepoint != null) {
                if (!success) {
                    connection.rollback(savepoint);
                }
                connection.releaseSavepoint(savepoint);
            }
        }
    });
}

经过一番研究,我发现在PostgreSQL中实现保存点可能会导致严重的性能问题,例如:

然而,这些博客文章中没有一个真正提供关于哪些保存点模式是安全的,哪些是不安全的信息,所以我的问题是:
在PostgreSQL中使用以下保存点模式是否安全:

savepoint s1;
select id from tbl where id=? for update nowait;
rollback to/release s1;

我确实看到XID增长是不可能避免的,但是我不确定它对性能的影响,其他陷阱呢?

6rvt4ljy

6rvt4ljy1#

使用这种模式是安全的,因为它不会产生错误的结果或破坏数据库,但它肯定会导致糟糕的性能。不要为每个单独的语句设置保存点。您必须更仔细地考虑,只在真正需要的地方设置它们,即在预期有时会失败的语句之前,但不应在它们失败时中止事务。
回答你的问题,并引用我的文章:进程数组存储在共享内存中,包含有关所有当前运行的后端的信息,每个会话最多可容纳64个未中止的子事务。此后,子事务ID将溢出到磁盘,这对性能不利。因此,每个事务设置的保存点不要超过64个,并记住PL/pgSQL构造BEGIN ... EXCEPTION ... END是使用保存点实现的。

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