我在NetBeans中只为一年编写了一个日历，对于GUI，我计划为一年设置一个典型的日历微调器。这种组合将确定一周中的哪一天是一个月的第一天和最后一天。
我编写的代码的问题是使用日历日按钮的名称作为变量。也许有一种方法可以为NetBeans准备一个语句来读取按钮名称？
对于这个日历，我创建了一个有49个按钮的JPanel（日历最多有7行星期），我尝试将每个按钮命名为“N（number）”（数字从1到49），这样我就可以创建一个for函数，使一个月的最后一天之后的那一天的位置成为下一个月的第一天的位置。
Image of the JPanel
这方面的代码将从2022年1月开始（不计算闰年）。日历的年份必须在“YearC”变量中指定（在这种情况下为2022）。还必须指定的另一个值是在“FirstD”变量中在一年的第一天之前日历中的空位置的数目（在2022年1月的情况下是5）。最后，我使用了一个微调器来表示月份，因为用户必须连续地选择月份，代码才能工作。
代码如下所示：
public void WeekPos(){
String MonIntCal = MonthCal.getValue().toString();
int DayN = 0;
int jub = 0;
int DayC = 0;
int FirstD = 6;
String YearC = "2022";
YearCal.setText(YearC);
String Nam = "B"+DayC;
int LastJan = 0;
int LastFeb = 0;
int LastMar = 0;
int LastApr = 0;
int LastMay = 0;
int LastJun = 0;
int LastJul = 0;
int LastAug = 0;
int LastSep = 0;
int LastOct = 0;
int LastNov = 0;
switch(MonIntCal){
case "January": DayN = 31; jub = 1;
case "February": DayN = 28; jub = 2;
case "March": DayN = 31; jub = 3;
case "April": DayN = 30; jub = 4;
case "May": DayN = 31; jub = 5;
case "June": DayN = 30; jub = 6;
case "July": DayN = 31; jub = 7;
case "August": DayN = 31; jub = 8;
case "September": DayN = 30; jub = 9;
case "October": DayN = 31; jub = 10;
case "November": DayN = 30; jub = 11;
case "December": DayN = 31; jub = 12;
}
switch(jub){
case 1: for (int i = 1; i<FirstD; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>DayN+FirstD; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN; i=i+1){
DayC = 5+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
}
LastJan = DayN+5;
case 2: for (int i = 1; i<LastJan; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastJan; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastJan+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastFeb = DayC;
}
};
case 3: for (int i = 1; i<LastFeb; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastFeb; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastFeb+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastMar = DayC;
}
};
case 4: for (int i = 1; i<LastMar; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastMar; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastMar+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastApr = DayC;
}
};
case 5: for (int i = 1; i<LastApr; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastApr; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastApr+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastMay = DayC;
}
};
case 6: for (int i = 1; i<LastMay; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastMay; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastMay+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastJun = DayC;
}
};
case 7: for (int i = 1; i<LastJun; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastJun; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastJun+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastJul = DayC;
}
};
case 8: for (int i = 1; i<LastJul; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastJul; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastJul+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastAug = DayC;
}
};
case 9: for (int i = 1; i<LastAug; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastAug; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastAug+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastSep = DayC;
}
};
case 10: for (int i = 1; i<LastSep; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastSep; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastSep+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastOct = DayC;
}
};
case 11: for (int i = 1; i<LastOct; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastOct; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastOct+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
if(i==DayN){
LastNov = DayC;
}
};
case 12: for (int i = 1; i<LastNov; i=i+1){
DayC = i;
Nam.setText(null);
}
for (int i = 49; i>LastNov; i=i-1){
DayC = i;
Nam.setText(null);
}
for (int i = 0; i<DayN+1; i=i){
DayC = LastNov+i;
if(DayC>49){
DayC=DayC-49;
}
Nam.setText(i.toString());
};
}
}
1条答案
按热度按时间e5nqia271#
为什么不将按钮存储在数组或ArrayList中，以便可以通过循环访问它们呢？我坚信无论如何都要通过循环来创建它们。