我想优化我的代码。我有很多重复,我相信这可以用一个循环来完成。
ciecg <- data.frame(baseline_cardinv_n = sum(d$cardinv_ecg1,na.rm=T),
baseline_total_n = table(d$cardinv_ecg1)[1]+table(d$cardinv_ecg1)[2],
baseline_pct = mean(d$cardinv_ecg1,na.rm=T)*100,
latest_cardinv_n = sum(d$cardinv_ecg2,na.rm=T),
latest_total_n = table(d$cardinv_ecg2)[1]+table(d$cardinv_ecg2)[2],
latest_pct = mean(d$cardinv_ecg2,na.rm=T)*100); rownames(ciecg) <- "ECG only"; ciecg
ciecghol <- data.frame(baseline_cardinv_n = sum(d$cardinv_ecg1_hol1,na.rm=T),
baseline_total_n = table(d$cardinv_ecg1_hol1)[1]+table(d$cardinv_ecg1_hol1)[2],
baseline_pct = mean(d$cardinv_ecg1_hol1,na.rm=T)*100,
latest_cardinv_n = sum(d$cardinv_ecg2_hol2,na.rm=T),
latest_total_n = table(d$cardinv_ecg2_hol2)[1]+table(d$cardinv_ecg2_hol2)[2],
latest_pct = mean(d$cardinv_ecg2_hol2,na.rm=T)*100); rownames(ciecghol) <- "ECG + HOL"; ciecghol
ciecgholec <- data.frame(baseline_cardinv_n = sum(d$cardinv_ecg1_hol1_ec1,na.rm=T),
baseline_total_n = table(d$cardinv_ecg1_hol1_ec1)[1]+table(d$cardinv_ecg1_hol1_ec1)[2],
baseline_pct = mean(d$cardinv_ecg1_hol1_ec1,na.rm=T)*100,
latest_cardinv_n = sum(d$cardinv_ecg2_hol2_ec2,na.rm=T),
latest_total_n = table(d$cardinv_ecg2_hol2_ec2)[1]+table(d$cardinv_ecg2_hol2_ec2)[2],
latest_pct = mean(d$cardinv_ecg2_hol2_ec2,na.rm=T)*100); rownames(ciecgholec) <- "ECG + HOL + TTE"; ciecgholec
round(rbind(ciecg,ciecghol,ciecgholec),1)
如果我在控制台中打印最后一行,我会得到:
> round(rbind(ciecg,ciecghol,ciecgholec),1)
baseline_cardinv_n baseline_total_n baseline_pct latest_cardinv_n latest_total_n latest_pct
ECG only 47 194 24.2 83 169 49.1
ECG + HOL 61 183 33.3 59 120 49.2
ECG + HOL + TTE 73 180 40.6 65 113 57.5
我想用一个循环来缩短我的代码,下面是我的尝试(我只是想让CIECG对我来说更简单):
ci_exam <- data.frame(matrix(nrow = 3,ncol = 0))
exam_1 <- c("cardinv_ecg1","cardinv_hol1","cardinv_ec1")
exam_2 <- c("cardinv_ecg2","cardinv_hol2","cardinv_ec2")
exam_name <- c("ECG only","HOL only","EC only")
for (i in 1:3) {
ci_exam[exam_name[i]] <- c(sum(d$exam_1[i],na.rm=T),
table(d$exam_1[i])[1]+table(d$exam_1[i])[2],
mean(d$exam_1[i],na.rm=T)*100,
sum(d$exam_2[i],na.rm=T),
table(d$exam_2[i])[1]+table(d$exam_2[i])[2],
mean(d$exam_2[i],na.rm=T)*100)
}
但给了我这个错误
Error in `[<-.data.frame`(`*tmp*`, exam_name[i], value = c(0, NA, NA, :
erstatning har 6 rækker, data har 3
In addition: Warning messages:
1: In mean.default(d$exam_1[i], na.rm = T) :
argument er ikke numerisk eller logisk: returnerer NA
2: In mean.default(d$exam_2[i], na.rm = T) :
argument er ikke numerisk eller logisk: returnerer NA
尝试创建一个循环。我希望在一个循环中创建整个 Dataframe (所有ciecg、ciecghol、ciecgholec组合在一个循环中,如命令循环所示(rbind(ciecg,ciecghol,ciecgholec),1))
1条答案
按热度按时间33qvvth11#
步骤1:将重复代码转换为函数
第2步;迭代参数并使用函数