我想在行中的框的底端对齐按钮（在波纹管卡的底端）。我有卡与行谁是分为两个部分-卡和框，我想框填充最大的其余行。我不能实现它，我会希望。波纹管我附上了当前代码的可视化。

。

@Composable
fun ProductItem(product: ProductModel, onItemClick: () -> Unit, onAddToCardButton: () -> Unit) {
    Card(
        modifier = Modifier
            .fillMaxSize()
            .padding(7.dp)
            .clickable { onItemClick() },
        shape = MaterialTheme.shapes.large,
        elevation = 4.dp
    ) {
        Row(
            modifier = Modifier.fillMaxSize()
        ) {
            Card(
                modifier = Modifier
                    .weight(1f),
                shape = MaterialTheme.shapes.small,
                elevation = 2.dp
            ) {
                Image(
                    painter = painterResource(id = R.drawable.ic_splash_screen),
                    contentDescription = "Image of ${product.name}",
                )
            }
            Box(
                modifier = Modifier
                    .weight(2f)
                    .fillMaxHeight()
                    .padding(6.dp)
                    .background(Color.Green)
            ) {
                Column(modifier = Modifier.align(Alignment.TopStart)) {
                    Text(
                        text = "${product.number}. ${product.name}",
                        fontWeight = FontWeight.Bold,
                        style = MaterialTheme.typography.h4,
                    )
                    Text(
                        text = product.ingredients, fontStyle = FontStyle.Italic
                    )
                }

                Button(
                    modifier = Modifier.align(Alignment.BottomEnd),
                    onClick = {
                        onAddToCardButton()
                    },
                    shape = RoundedCornerShape(8.dp),
                ) {
                    if (product.type == "pizza") {
                        Text(text = "od ${String.format("%.2f", product.price[0])} zł")
                    } else {
                        Text(text = "${String.format("%.2f", product.price[0])} zł")

                    }
                }
            }
        }
    }
}