我试图用嵌套的金额对一个集合求和(按月/年计算支出)-没有运气。
这是收集(摘录):
[
{
"_id" : ObjectId("5faaf88d0657287993e541a5"),
"segment" : {
"l1" : "Segment A",
"l2" : "001"
},
"invoiceNo" : "2020.10283940",
"invoicePos" : 3,
"date" : ISODate("2019-09-06T00:00:00.000Z"),
"amount" : {
"document" : {
"amount" : NumberDecimal("125.000000000000"),
"currCode" : "USD"
},
"local" : {
"amount" : NumberDecimal("123.800000000000"),
"currCode" : "CHF"
},
"global" : {
"amount" : NumberDecimal("123.800000000000"),
"currCode" : "CHF"
}
}
},
...
]
我想用“全球”货币总结每月的总发票量。
我在MongoDB上尝试了这个查询:
db.invoices.aggregate(
{$project : {
month : {$month : "$date"},
year : {$year : "$date"},
amount : 1
}},
{$unwind: '$amount'},
{$group : {
_id : {month : "$month" ,year : "$year" },
total : {$sum : "$amount.global.amount"}
}})
我得到的结果是:
/* 1 */
{
"_id" : ObjectId("5faaf88d0657287993e541a5"),
"amount" : {
"document" : {
"amount" : NumberDecimal("125.000000000000"),
"currCode" : "USD"
},
"local" : {
"amount" : NumberDecimal("123.800000000000"),
"currCode" : "CHF"
},
"global" : {
"amount" : NumberDecimal("123.800000000000"),
"currCode" : "CHF"
}
},
"month" : 9,
"year" : 2019
}
/* 2 */
{
"_id" : ObjectId("5faaf88d0657287993e541ac"),
"amount" : {
"document" : {
"amount" : NumberDecimal("105.560000000000"),
"currCode" : "CHF"
},
"local" : {
"amount" : NumberDecimal("105.560000000000"),
"currCode" : "CHF"
},
"global" : {
"amount" : NumberDecimal("105.560000000000"),
"currCode" : "CHF"
}
},
"month" : 11,
"year" : 2020
}
但是,这并不是每月所有发票的总和,而是看起来像单个发票行-没有汇总。
我想得到这样一个结果:
[
{
"month": 11,
"year": 2020,
"amount" : NumberDecimal("99999.99")
},
{
"month": 10,
"year": 2020,
"amount" : NumberDecimal("99999.99")
},
{
"month": 9,
"year": 2020,
"amount" : NumberDecimal("99999.99")
}
]
我的查询有什么问题?
2条答案
按热度按时间cwdobuhd1#
这会有帮助吗?
Playground
如果你需要任何额外的解释,让我知道,但代码是相当短和不言自明的。
rjee0c152#
原则上你的聚合管道是好的,有几个错误:
$unwind
是无用的,因为$amount
不是数组。简单明了: