有没有办法编写一个for循环,以便下面的代码可以生成m=0,1
的输出?现在,我手动使用m=0
和m=1
。我给出了当前和预期的输出。
import numpy as np
T2=[[0, 3, 5, 8, 9, 10, 11],[0, 2, 3, 5, 6, 8, 9, 10, 11]]
X=np.array([np.array([4.17551036e+02, 3.53856161e+02, 2.82754301e+02, 1.34119055e+02,
6.34573886e+01, 2.08344718e+02, 1.00000000e-24]) ,
np.array([4.17551036e+02, 3.32821605e+02, 2.94983702e+02, 2.78809292e+02,
1.26991664e+02, 1.36026510e+02, 8.31512525e+01, 2.07329562e+02,
1.00000000e-24]) ],
dtype=object)
C1=0.0
index=0
m=0/1
for j in range(T2[m][-1]):
if(j!=T2[m][index]):
X[m] = np.insert(X[m], j, C1, axis=None)
else:
index+=1
print([X[m]])
当前输出为
m=0:
[array([4.17551036e+02, 0.00000000e+00, 0.00000000e+00, 3.53856161e+02,
0.00000000e+00, 2.82754301e+02, 0.00000000e+00, 0.00000000e+00,
1.34119055e+02, 6.34573886e+01, 2.08344718e+02, 1.00000000e-24])]
m=1:
[array([4.17551036e+02, 0.00000000e+00, 3.32821605e+02, 2.94983702e+02,
0.00000000e+00, 2.78809292e+02, 1.26991664e+02, 0.00000000e+00,
1.36026510e+02, 8.31512525e+01, 2.07329562e+02, 1.00000000e-24])]
预期的输出为
array([array([4.17551036e+02, 0.00000000e+00, 0.00000000e+00, 3.53856161e+02,
0.00000000e+00, 2.82754301e+02, 0.00000000e+00, 0.00000000e+00,
1.34119055e+02, 6.34573886e+01, 2.08344718e+02, 1.00000000e-24]),
array([4.17551036e+02, 0.00000000e+00, 3.32821605e+02, 2.94983702e+02,
0.00000000e+00, 2.78809292e+02, 1.26991664e+02, 0.00000000e+00,
1.36026510e+02, 8.31512525e+01, 2.07329562e+02, 1.00000000e-24]) ],dtype=object)
1条答案
按热度按时间8yparm6h1#
添加外部
for
循环: