我正在尝试在我的shell脚本中进行curl调用，我想在其中以数据的形式传递sql的结果。

taleResult = `isql -S$envServer -U$USERNAME -h -b << ENDSQL | grep -vE "^Password: $"
$PASSWORD
set nocount on
GO
USE db_cfg
GO
SELECT tablename from MyTable
GO
ENDSQL`

表结果类似于TableA TableB TableC

liveCalculators=()
if echo "$tableResult"; then
            for line in $tableResult
            do
                MessageLog "Table is $line"
                liveCalculators+=(\"$line\")
            done
endif

假设我将结果存储在数组中，格式为liveCalculators

curl_response=` curl_response=`curl -k -X POST "https://myapiurl" \
                -H "accept: */*" \
                -H "Content-Type: application/json" \
                -w ";%{http_code}" \
                -d "@/dev/stdin" <<EOF
                 { "keys": [],, "calcs": ${liveCalculators[@]}}
                EOF`
`

我收到错误请求
请建议可以做些什么来修复它。